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3 years ago

An induced charge is when charged particles can be attracted to neutral objects. True or false?

Physics

1 answer:

Sindrei [870]3 years ago

5 0

Answer:

the answer is true Induction charging is a method used to charge an object without actually touching the object to any other charged object.

Explanation:

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A force produces an acceleration of 5 ms

Dmitrij [34]

F = m • a (I. Newton)

F = (4 kg) x (5 m/s^2)

F = 20 Newtons

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3 years ago

What is your height in centimeters? what is your weight in Newton's

goldfiish [28.3K]

My height is 178 centimeters.
My weight is 700N.

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3 years ago

Read 2 more answers

Two charged particles are placed 2.0 meters apart. The first charge is +2.0 E-6 C, and the second charge is +4.0 E-6 C. What is

Anestetic [448]

The electrical force between the two charges can be calculated as +1.8×10⁻² N and its repulsive.

To find the electrical force, distance = 2 meters

charge q1 = 2×10⁻⁶ C

charge q2 = 4×10⁻⁶ C

<h3>Define coulomb's law and solve with formula.</h3>

The force of attraction or repulsion acting along a straight line between two electric charges is directly proportional to the product of the charges and inversely to the square of the distance between them.

Formula can be written as,

F = K ( q1q2 / r² )

F - electric force

k - Coulomb constant

q1, q2 - charges

r - distance of separation

Substituting the values in the formula,

F = 9 × 10⁹ Nm²/C² ( (2×10⁻⁶ C × 4×10⁻⁶ C) / (2²))

= 0.0179751

F = 1.8 × 10 ⁻² N.

As both the charges q1 and q2 are positive, the charges gets repulsive.

SO, the correct answer is Option A.

Learn more about coulomb's law,

brainly.com/question/506926

#SPJ1

8 0

2 years ago

A 1200 kg cannon fires a 100.0 kg cannonball at 52 m/s. What is the recoil velocity of the cannon? Assume that frictional forces

alina1380 [7]

Answer:

A) 4.3 m/s

Explanation:

M = mass of the cannon = 1200 kg

m = mass of the cannonball = 100 kg

v = speed of the cannonball after the fire = 52 m/s

V = speed of cannon after fire

Since the cannon and cannonball were at rest before fire, total initial momentum will be taken as 0

Using conservation of momentum

0 = m v - M V

M V = m v

inserting the values

(1200) V = (100) (52)

V = 4.3 m/s

8 0

3 years ago

A negative charge -0.550 HC exerts an upward 0.700 N force on an unknown charge 0.220 m directly below it. (a) What is the unkno

Sonja [21]

Answer:

Part a)

$q_2 = -6.8 \mu C$

Part b)

$F = 0.700 N$

direction = downwards

Explanation:

As we know that the negative charge will experience the force due to some other charge below it

the force is given as

$F = 0.700 N$

now we know that

$F = \frac{kq_1q_2}{r^2}$

now plug in all data

$0.700 = \frac{(9 \times 10^9)(0.550\mu C)q_2}{0.220^2}$

$0.700 = 1.022\times 10^5 q_2$

$q_2 = -6.8 \mu C$

since this is a repulsion force so it must be a negative charge

Part b)

As per Newton's III law it will exert equal and opposite force on it

So here the force on the charge below it will be same in magnitude but opposite in direction

so here we have

$F = 0.700 N$

direction = downwards

4 0

3 years ago