9 - 2c + c = -13
9 - 3c = -13
-3c = -22
c = 7 1/3
<u>Solution</u>:
It is given that length of a rectangular room is 6.9 m and its width is 9.6 m.
So We have ;
- Length of Rectangular room = 6.9 m
- Length of Rectangular room = 6.9 m Width of Rectangular room = 9.6 m
<u>So We have to find the area of the room.</u>
We know :
<h3>Area of Rectangle = Length times Width </h3>
<u>Area of Rectangular room = Length of Rectangular room × Width of Rectangular room </u>
Area of Rectangular room = 6.9 m × 9.6 m
Area of Rectangular room = 6.9 m × 9.6 m Area of Rectangular room = 66.24 m²
Therefore, Required area of the room is 66.24 m².
Answer:
- domain: x ≥ 7
- range: f(x) ≥ 9
Step-by-step explanation:
The domain is the set of values of x for which the function is defined. Those are the values of x that make the square root argument non-negative:
x -7 ≥ 0
x ≥ 7
__
Since the square root cannot be negative, the sum of it and 9 cannot be less than 9. The range is ...
f(x) ≥ 9
The answer is 1.75 hope thishelps
Identity: sec^2(x) = 1 + tan^2(x) => tan^2(x) = sec^2 (x) - 1
sec(x) = √[37/6] => sec^2 (x) = 37/6
tan^2 (x) = 37/6 - 1 = 31/6
tan (x) = +/- √[31/6]
Given that sin (x) is negative and sec (x) is positive, we are in the fourth quadrant, so the tangent is negative, then:
tan (x) = - √[31/6] = - 2.27
