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3 years ago

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(please help me)The center of a circle is at (8, —8). One point on the circle is at (8, —3). What is the area of the circle? (Us

e 3.14 for pi.)
A 15.7 units^2

B 64 units^2

C 78.5 units^2

D 200.96 units^2

1 answer:

Serjik [45]3 years ago

7 0

Answer:

it A or C depending on the site you use

Step-by-step explanation:

good luck

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Use Pascal’s Triangle to determine the fifth term of the expansion of (x + 3)7

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Step-by-step explanation:

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Term 5 = 7C4 * x^5 * 3^4

= 35 * x^5 * 3^4

= 2835x^5.

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2 years ago

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A student created this table to represent a linear relationship between x and y.X Y-2. 10.0-1. 7.50. 5.01. 2.52. 0The student sa

alex41 [277]

The relationship between x and y is represent as:

Since, the relationship is linear.

The standard form of equation of line is:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

Consider any two set x and y values from the given relationship.

Let (-2, 10) and (-1,7.5)

$\text{Substitute x}_1=-2,y_1=10,x_2=-1,y_2=7.5\text{ in the standard equation of line.}$

$\begin{gathered} y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1) \\ y-10=\frac{7.5-10}{-1-(-2)}(x-(-2)) \\ y-10=\frac{-2.5}{1}(x+2) \\ y-10=-2.5(x+2) \\ y=-2.5(x+2)+10 \end{gathered}$

The equation of the linear relationship between x and y is:

y = -2.5(x + 2) + 10

Now, to check that the point (9, -17.5) lies on the represented relationship between x and y

Substitute x = 9 and y = -17.5 in the equation y = -2.5(x + 2) + 10

y = -2.5(x + 2) + 10

-17.5 = -2.5(9 + 2) + 10

-17.5 = -2.5(11) + 10

-17.5 = -27.5 + 10

-17.5 = -17.5

Thus, LHS = RHS

Hence the point (9, -17.5) lie on the given linear relationship between x and y.

Answer: The point (9, -17.5) lie on the given linear relationship between x and y.

8 0

1 year ago

Show work please thank you

Alenkinab [10]

Hey there!:)

b1+b2
--------- x h =area
2

(3+5)/2h=area

8/2h=area

4(2)=area
area= 8ft squared (this is your answer)

Hope this helps! Let me know if you need more help:)

8 0

3 years ago