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Lelechka [254]
3 years ago
7

What is the mass of a ink pen with triple beam balance

Chemistry
1 answer:
Gnesinka [82]3 years ago
7 0
The mass of an ink pen with a triple beam balance if all the weights positioned to the right would be a maximum of 610 grams which sounds rather heavy for an ink pen but in the absence of necessary information it seems that that would have to be the answer.
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A solution is prepared by dissolving ammonium sulfate in enough water to make of stock solution. A sample of this stock solution
Pani-rosa [81]

Answer: molarity of ammonium ions = 0.274mol/L

molarity of sulfate ions = 0.137mol/L

<em>Note: The complete question is given below</em>

A solution is prepared by dissolving 10.8 g ammonium sulfate in enough water to make 100.0 mL of stock solution. A 10.00-mL sample of this stock solution is added to 50.00 mL of water. Calculate the concentration of ammonium ions and sulfate ions in the final solution.

Explanation:

Molar concentration = no of moles/volume in liters

no of moles = mass/molar mass

mass of ammonium sulfate = 10.8g, molar mass of ammonium sulfate, (NH₄)₂SO₄ = (14+4)*2 + 32+ (16)*4 = 132g/mol

no of moles = 10.8g/132g/mol = 0.0820moles

<em>Molarity of stock solution = 0.0820mol/(100ml/1000ml* 1L) = 0.0820mol/0.1L Molarity of stock solution = 0.820mol/L</em>

Concentration of final solution is obtained from the dilution formula,

<em>C1V1 = C2V2</em>

C1 = 0.820M, V1 = 10mL, C2 = ?, V2 = 60mL

C2 = C1V1/V2

C2 = 0.820*10/60 = 0.137mol/L

molar concentration of ions = molarity of solution * no of ions

molarity of ammonium ions = 0.137mol/L * 2 = 0.274mol/L

molarity of sulfate ions = 0.137 mol/L * 1 = 0.137mol/L

4 0
4 years ago
If 1,000 mL = 1 L, which of the following are possible conversion factors for liters and milliliters? Check all that apply.
Fudgin [204]

Answer:

Two conversion factors:

         1=\dfrac{1L}{1,000ml}\\ \\ \\ 1=\dfrac{1,000mL}{1L}

Explanation:

You can create two possible <em>conversion factors</em>, one to convert from mL to L, and one to convert from L to mL

<u />

<u>a) From mL to L</u>

To convert mL to L you need to multiply by a conversion factor that has mL on the denominator and L in the numerator.

Your starting point is: 1,000mL=1L

Then, divide both sides by 1,000mL (this will be on the denominator of the fraction);

       1,000mL=1L\\\\ \\\dfrac{1,000ml}{1,000mL}=\dfrac{1L}{1,000mL}\\ \\ \\ 1=\dfrac{1L}{1,000mL}

<u>b) From L to mL</u>

Divide both sides by 1 L:

            1,000mL=1L\\\\ \\\dfrac{1,000ml}{1L}=\dfrac{1L}{1L}\\ \\ \\ 1=\dfrac{1,000mL}{1L}

7 0
3 years ago
Read 2 more answers
You will be reading from an essay and a play dealing with the lives of women in the late eighteenth and early
s344n2d4d5 [400]

Answer:

all work

Explanation:

6 0
3 years ago
Read 2 more answers
Solve question 4a least reactive to most reactive
denis23 [38]
Nickel (II) oxide, iron (III) oxide, chromium (III) oxide, magnesium oxide
7 0
3 years ago
Need some help please
Marysya12 [62]
Number 3:
Chlorine, Sodium, Sulfate, Magnesium, and Calcium.
Number 4:
The salt Increases/Decreases the density.
Hope this helps you! 
:)
5 0
3 years ago
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