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Aleksandr [31]
3 years ago
5

What is the total Mass of Reactants in Alpha Decay

Chemistry
2 answers:
sweet [91]3 years ago
8 0

Answer:

Calcite Calcium carbonate

Calgon Calcium hexametaphosphate

Calomel Mercurous chloride

Carbolic acid Phenol

Explanation:

⭐ sorry ⭐

Naddik [55]3 years ago
6 0

Ey do.pe bro if u keep posting free pts ur gonna get ur account deleted or banned.

Btw what did u mean by trolling ppl ?

Have a nice day do.pe bro lol

Ur my new bestie lm.ao

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A balloon is filled with 0.250 mole of air at 35°C. If the volume of the balloon is 6.23 liters, what is the absolute pressure o
Jobisdone [24]
X= 101.325 kPa
The absolute pressure of the air in the balloon is 101.325 kilopascals.
6 0
3 years ago
When the procedure calls for making a more dilute solution of an acid, or mixing an acid with other solutions, what is the corre
Fed [463]

Answer:

The correct order it b. always add acid last.

Explanation:

Adding acid first could result on a violent reaction and heat or fumes can be generated. The best approach is to always add all the water or non-acid component first, or add a significant portion before adding the acid slowly to the mixture.

7 0
3 years ago
Does the volume change if a ballon is put in a freezer
Lorico [155]
It gets smaller so yes
6 0
3 years ago
How many moles of Al would be produced from 20 moles of Al2O3?<br> 2Al2O3<br> -&gt;<br> 4A1 + 302
Evgesh-ka [11]
<h3>Answer:</h3>

\displaystyle 40 \ mol \ Al

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2Al₂O₃ → 4Al + 3O₂

[Given] 20 mol Al₂O₃

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Al₂O₃ → 4 mol Al

<u>Step 3: Stoich</u>

  1. [DA] Set up:                                                                                                     \displaystyle 20 \ mol \ Al_2O_3(\frac{4 \ mol \ Al}{2 \ mol \ Al_2O_3})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 40 \ mol \ Al

<u>Step 4:Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

Since our final answer already has 1 sig fig, there is no need to round.

4 0
2 years ago
Please let me know if this is correct?
siniylev [52]

Answer: Yes! you're all good. Alkali metals in group 1 are the most metallic :)

6 0
3 years ago
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