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kirill115 [55]
2 years ago
9

A sample of damp air in a 1.00 L container exerts a total pressure of 741.0 torr at 20 oC; but when it is cooled to -10 oC, the

water vapor freezes to ice with neglegible pressure giving a pressure of 607.1 torr. How many molecules of water were present in the gas
Chemistry
1 answer:
AlexFokin [52]2 years ago
5 0

From the information presented in the question, the number of molecules present of water present is obtained 2.41 × 10^21 molecules.

From the information we have;

Volume of the damp air =  1 L

Pressure of the damp air =  741.0 torr or 0.975 atm

Temperature of the gas = 20 oC + 273 = 293 K

R = 0.082 atm LK-1mol-1

Number of moles = ?

n =PV/RT

n = 0.975 × 1/0.082 ×  293

n = 0.041 moles

Volume of water vapor = 1 L

Temperature of water = -10 oC + 273 = 263 K

Pressure of the gas = 607.1 torr or 0.799 atm

R = 0.082 atm LK-1mol-1

n= PV/RT

n = 0.799 × 1/ 0.082 × 263

n = 0.037 moles

Number of moles of water = 0.041 moles -  0.037 moles = 0.004 moles

If 1 mole = 6.02 × 10^23 molecules

0.004 moles = 0.004 moles × 6.02 × 10^23 molecules/1 mole

= 2.41 × 10^21 molecules

Learn more: brainly.com/question/2510654

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Why is it permissible to use a wet bottle when first obtaining your kmno4 solution?
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5 0
3 years ago
What is the mass in grams of 2.6 moles of angelic acid?
Dennis_Churaev [7]

Answer:

260.34g

Explanation:

First, you need to know what angelic acid is comprised of. It is written as C₅H₈O₂.

In order to solve for the mass of 2.6 moles of angelic acid, you need the mass of 1 mole of angelic acid. This can be found by adding the masses from the periodic table, like shown below:

5 carbon atoms = (5)(12.01g) = 60.05g

8 hydrogen atoms = (8)(1.01) = 8.08g

2 oxygen atoms = (2)(16) = 32g

angelic acid = 60.05 + 8.08 + 32 = 100.13g

Then, set up a basic stoichiometric equation and solve. The units should cancel out.

(\frac{2.6mol}{1} )(\frac{100.13g}{1mol} )=260.34g

5 0
3 years ago
Convert 7.1x10^25 molecules of water to moles
ruslelena [56]

Answer:

<h2>117.94 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{7.1 \times  {10}^{25} }{6.02 \times  {10}^{23} }  \\  = 117.940199...

We have the final answer as

<h3>117.94 moles</h3>

Hope this helps you

8 0
2 years ago
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