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wlad13 [49]
3 years ago
14

WILL GIVE BRAINLYEST!!!!!The number at the bottom of Silicon on the periodic table is 28.086. This number is the element's _____

________.
silicon
14
SI
28.086

Question 10 options:

atomic weight


symbol


atomic number


electron number
Chemistry
2 answers:
Leto [7]3 years ago
7 0

Answer:

atomic weight

Explanation:

its atomic weight becuase if it a number on the peroidic table its going to be the atomic weight

Natalka [10]3 years ago
6 0

Answer:

I don't

Explanation:

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<em>First, it should be understood that an endothermic reaction is one that absorbs energy in the form of heat from the surrounding.</em> The products of endothermic reactions usually have higher energy than their reactants. Hence, the ΔH° which is referred to as the enthalpy change is usually positive.

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What advantage does a heterogeneous catalyst provide over a homogeneous catalyst in industrial processes?
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Wastewater from a cement factory contains 0.280 g of Ca2+ ion and 0.0220 g of Mg2+ ion per 100.0 L of solution. The solution den
faltersainse [42]

<u>Answer:</u> The concentration of Ca^{2+}\text{ and }Mg^{2+} ions are 2.797 ppm and 0.212 ppm respectively.

<u>Explanation:</u>

To calculate the mass of solution, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Volume of gold = 100 L = 100000 mL    (Conversion factor:  1 L = 1000 mL)

Density of gold = 1.001 g/mL

Putting values in above equation, we get:

1.001g/mL=\frac{\text{Mass of solution}}{100000mL}\\\\\text{Mass of solution}=1.001\times 10^5g

To calculate the concentration in ppm (by mass), we use the equation:

ppm=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6

  • <u>Calculating the concentration of calcium ions:</u>

Mass of Ca^{2+ ions = 0.280 g

Putting values in above equation, we get:

ppm(Ca^{2+})=\frac{0.280g}{1.001\times 10^5}\times 10^6=2.797ppm

  • <u>Calculating the concentration of magnesium ions:</u>

Mass of Mg^{2+ ions = 0.0220 g

Putting values in above equation, we get:

ppm(Mg^{2+})=\frac{0.0220g}{1.001\times 10^5}\times 10^6=0.212ppm

Hence, the concentration of Ca^{2+}\text{ and }Mg^{2+} ions are 2.797 ppm and 0.212 ppm respectively.

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3 years ago
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