Answer:
3 factors that are required for biodegradation are
a) Appropriate moisture
b) Oxygen supply
c) Stable condition
Explanation:
For biodegradation in a landfill, following conditions are essential –
a) Appropriate moisture
b) Oxygen supply
c) Stable condition
Contrast to above three conditions, the waste in landfill is kept dry, devoid of oxygen supply, and stirred continuously due to which the organic matter mummify instead of decomposing.
Mass of cisplatin can be made : 144.6 g
<h3>Further explanation</h3>
Given
Reaction(unbalanced)
K2PtCl4 (aq) + ___NH3 (aq) ___Pt(NH3)2Cl2 (s) + ___KCl (aq)
200 g of K2PtCl4
Required
mass of cisplatin Pt(NH3)2Cl2
Solution
Balanced equation
K₂PtCl₄ (aq) + 2NH₃ (aq) ⇒Pt(NH₃)₂Cl₂ (s) + 2KCl (aq)
mol of K₂PtCl₄(MW=2.39+195+4.35.5=415 g/mol) :
mol = mass : Mw
mol = 200 : 415
mol = 0.482
From equation, mol ratio K₂PtCl₄ : Pt(NH₃)₂Cl₂ = 1 : 1, so mol Pt(NH₃)₂Cl₂ = 0.482
Mass of cisplatin Pt(NH₃)₂Cl₂(MW=195+2.14+6.1+2.35.5=300 g/mol) :
mass = mol x MW
mass = 0.482 x 300
mass = 144.6 g
Answer:
C
Explanation:
Fresh water fish need freshwater.
Glucose has empirical formula C6H12O6. So its formula mass can be calculated from that: 12.01x6 + 1.008x12 + 16.00x6 = 72.06 + 12.096 + 96.00 = 180.156 which needs to be rounded to two decimals to get 180.16 g/mole<span>.</span>
The balanced equations for the formation of potassium suberate from cyclooctene are;
3KMnO4 + 3C8H18 + 4H2O --> 3C8H17(OH)2 + 2MnO2 + 2KOH and
3C8H14(OH)2 + 6KMnO4 ----> 3KCOO(CH2)6 COOK + 6MnO2 + 6H20
<h3>What is potassium suberate ?</h3>
The compound potassium suberate is obtained from cyclooctene. The first step in the process is the oxidation of cyclooctene using potassium permanganate as follows;
3KMnO4 + 3C8H18 + 4H2O --> 3C8H17(OH)2 + 2MnO2 + 2KOH
This is followed by the production of potassium suberate from the reaction equation;
3C8H14(OH)2 + 6KMnO4 ----> 3KCOO(CH2)6 COOK + 6MnO2 + 6H20
Learn more about potassium suberate: brainly.com/question/8507057?
