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Marina86 [1]
2 years ago
5

The valence electrons of a krypton (Kr) atom in the ground state are located in the

Chemistry
1 answer:
egoroff_w [7]2 years ago
6 0

Answer:

D

Explanation:

The valence electrons are the outer electrons and must be located in the outermost shell. In this case, D.

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How many liters of 
Kruka [31]
The balanced equation for the above reaction is as follows
C₆H₁₂O₆(s) + 6O₂(g) --> 6H₂O(g) + 6CO₂<span>(g)
the limiting reactant in the equation is glucose as the whole amount of glucose is used up in the reaction.  
the amount of </span>C₆H₁₂O₆ used up - 13.2 g
the number of moles reacted - 13.2 g/ 180 g/mol  = 0.073 mol
stoichiometry of glucose to CO₂ - 1:6
then number of CO₂ moles are - 0.073 mol x 6 = 0.44 mol
As mentioned this reaction takes place at standard temperature and pressure conditions, 
At STP 1 mol of any gas occupies 22.4 L
Therefore 0.44 mol of CO₂ occupies 22.4 L/mol  x 0.44 mol = 9.8 rounded off - 10.0 L
Answer is B) 10.0 L CO₂
3 0
3 years ago
Paul added a sample of bromic acid to water and found the pOH to be 10. What is the pH of the solution?
Ket [755]

Answer:

Explanation:

pH + pOH = 14

pH + 10 = 14

pH = 14 - 10 = 4

Therefore pH of the solution is 4 .

6 0
2 years ago
What are the uses of glycerin?<br>​
Ilia_Sergeevich [38]

Explanation:

This medication is used as a moisturizer to treat or prevent dry, rough, scaly, itchy skin and minor skin irritations (e.g., diaper rash, skin burns from radiation therapy). Emollients are substances that soften and moisturize the skin and decrease itching and flaking.

6 0
3 years ago
At 311 K, this reaction has a K c value of 0.0111 . X ( g ) + 2 Y ( g ) − ⇀ ↽ − 2 Z ( g ) Calculate K p at 311 K. Note that the
Aleks [24]

Answer:

K_{p}=4.35\times 10^{-4}

Explanation:

We know, K_{p}=K_{c}(RT)^{\Delta n}

where, R = 0.0821 L.atm/(mol.K), T is temperature in kelvin and \Delta n is difference in sum of stoichiometric coefficient of products and reactants

Here \Delta n=(2)-(2+1)=-1 and T = 311 K

So, K_{p}=(0.0111)\times [(0.0821L.atm.mol^{-1}.K^{-1})\times 311K]^{-1}=4.35\times 10^{-4}

Hence value of equilibrium constant in terms of partial pressure (K_{p}) is 4.35\times 10^{-4}

4 0
3 years ago
You have a big block of ice you chip off a small chunk which has more thermal energy?
gayaneshka [121]
I think ita c sense its the same object
3 0
2 years ago
Read 2 more answers
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