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docker41 [41]
3 years ago
14

Draw graph x + y = 7 and x - y = 2 on the same graph

Mathematics
2 answers:
borishaifa [10]3 years ago
8 0

Graphed in attached file and drawn!

trapecia [35]3 years ago
6 0

Answer:

see attachment

Step-by-step explanation:

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Please I only need number 2​
babunello [35]
-249/20 seems like the answer
7 0
3 years ago
What is he slope and y intercept for the line Y=-4x+2​
Sav [38]

y=mx+b

slope is also m

b is the y-intercept

Y=-4x+2​

answer:

slope=-4, y-intercept=2

7 0
3 years ago
Review Word Problems ?
melomori [17]
1.) 2=50%

2.) 25% of 30,000= 7500
4 0
4 years ago
A rectangular playground is to be fenced off and divided in two by another fence parallel to one side of the playground. Three h
neonofarm [45]

Answer:

  • 50 ft by 75 ft
  • 3750 square feet

Step-by-step explanation:

Let x represent the length of the side not parallel to the partition. Then the length of the side parallel to the partition is ...

  y = (300 -2x)/3

And the enclosed area is ...

  A = xy = x(300 -2x)/3 = (2/3)(x)(150 -x)

This is the equation of a parabola with x-intercepts at x=0 and x=150. The line of symmetry, hence the vertex, is located halfway between these values, at x=75.

The maximum area is enclosed when the dimensions are ...

  50 ft by 75 ft

That maximum area is 3750 square feet.

_____

<em>Comment on the solution</em>

The generic solution to problems of this sort is that half the fence (cost) is used in each of the orthogonal directions. Here, half the fence is 150 ft, so the long side measures 150'/2 = 75', and the short side measures 150'/3 = 50'. This remains true regardless of the number of partitions, and regardless if part or all of one side is missing (e.g. bounded by a barn or river).

6 0
3 years ago
Which of the following equations is of the parabola whose vertex is at (2, 3), axis of symmetry parallel to the y-axis and p = 4
lora16 [44]

Answer:

option A.) y-3 = 1/16 (x-2)^2

Step-by-step explanation:

we know that

If the axis of symmetry is parallel to the y-axis, then we have a vertical parabola

The equation of a vertical parabola is equal to

4p(y-k)=(x-h)^{2}

where

(h,k) is the vertex

In this problem we have

(h,k)=(2,3)

p=4

substitute

4(4)(y-3)=4(4)(x-2)^{2}

16(y-3)=(x-2)^{2}

(y-3)=(1/16)(x-2)^{2}

8 0
3 years ago
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