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NemiM [27]
3 years ago
5

an alligator can run at a speed of 13 feet per second on land at this rate how far can it run in 3 seconds

Mathematics
2 answers:
Mrac [35]3 years ago
7 0
13*3=39
the alligator can run 39ft per second
WARRIOR [948]3 years ago
3 0
39 feet because if you multiply 13 and 3 its 39
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A trucking firm has a large inventory of spare parts that have been in storage for a long time. It knowsthat some proportion of
Debora [2.8K]

Answer:

0.1546\leq \widehat{p}\leq 0.3513

Step-by-step explanation:

The firm tests 75 parts, and finds that 0.25 of them are notusable

n = 75

x = 0.25 \times 75 = 18.75≈19

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{19}{75}

\widehat{p}=0.253

Confidence level = 95%

So, Z_\alpha at 95% = 1.96

Formula of confidence interval of one sample proportion:

=\widehat{p}-Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}\leq \widehat{p}\leq \widehat{p}+Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}

=0.253-(1.96)\sqrt{\frac{0.253(1-0.253)}{75}}\leq \widehat{p}\leq0.253+(1.96)\sqrt{\frac{0.253(1-0.253}{75}}

Confidence interval =0.1546\leq \widehat{p}\leq 0.3513

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Step-by-step explanation:

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Read 2 more answers
Consider two vectors A and B A=14i and B= -4i+8j
DaniilM [7]
Assuming \mathbf a,\mathbf b\in\mathbb R^3, you have

\mathbf a\cdot\mathbf b=(14)(-4)+(0)(8)=-56

so

((\mathbf a\cdot\mathbf b)\,\mathbf i)\cdot\mathbf a=(-56\,\mathbf i)\cdot(14\,\mathbf i)=(-56)(14)=-784

Next,

\mathbf a+\mathbf b=(14\,\mathbf i)+(-4\,\mathbf i+8\,\mathbf j)=10\,\mathbf i+8\,\mathbf j

Then

(\mathbf a+\mathbf b)\times\mathbf b=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\10&8&0\\-4&8&0\end{vmatrix}=112\,\mathbf k

((\mathbf a+\mathbf b)\times\mathbf b)\times\mathbf k=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\0&0&112\\0&0&1\end{vmatrix}=\mathbf 0
4 0
3 years ago
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