-3/-4(8x-12)=5x-2 how do I solve this

Mathematics

2 answers:

natta225 [31]4 years ago

4 0

The answer would be x equals 7

ohaa [14]4 years ago

3 0

1 Two negatives make a positive
\frac{3}{4}(8x-12)=5x-2
4

3
(8x−12)=5x−2

2 Simplify \frac{3}{4}(8x-12)
4

3
(8x−12) to \frac{3(8x-12)}{4}
4

3(8x−12)

\frac{3(8x-12)}{4}=5x-2
4

3(8x−12)
=5x−2

3 Factor out the common term 44
\frac{3\times 4(2x-3)}{4}=5x-2
4

3×4(2x−3)
=5x−2

4 Simplify 3\times 4(2x-3)3×4(2x−3) to 12(2x-3)12(2x−3)
\frac{12(2x-3)}{4}=5x-2
4

12(2x−3)
=5x−2

5 Simplify \frac{12(2x-3)}{4}
4

12(2x−3)
to 3(2x-3)3(2x−3)
3(2x-3)=5x-23(2x−3)=5x−2

6 Expand
6x-9=5x-26x−9=5x−2

7 Add 99 to both sides
6x=5x-2+96x=5x−2+9

8 Simplify 5x-2+95x−2+9 to 5x+75x+7
6x=5x+76x=5x+7

9 Subtract 5x5x from both sides
6x-5x=76x−5x=7

10 Simplify 6x-5x6x−5x to xx
x=7x=7

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jill brought 2 1/3 boxes of carrot muffins for a bake sale mike bought 1 3/4 boxes of apple muffins what is the total number of

ioda

To solve this, we need to find the LCM (Least Common Multiple) for 3 and 4 to have common denominator. 3 x 4 is 12.

So let us keep in mind 1 in this case is 12/12, and 2 is 24/12

2 of 2 1/3 is 24/12.

Let us find out 1/3

12 divided by 3 is 4, so we multiply both sides by 4.

1/3 x 4/4 is 4/12. 4/12 plus 24/12 is 28/12 equaling 2 and 4/12, or , if you simplified, 2 and 1/3

Now to find 1 and 3/4

1 is 12/12, and the easiest way to find 3/4 is to do 1/4 x 3 or 4/4 - 1/4. (I'm doing the first way)

12 divided by 4 is 3. we times both sides by 3. 1/4 x 3/3 = 3/12. since 3/4 is 1/4 x 3/1, we multiply 3/12 by 3/1, which equals 9/12.

1 (12/12) plus 3/4 (9/12) equals 21/12, or 1 and 3/4 simplified

Now we add 2 1/3 (28/12) by 1 3/4 (21/12) , we get 4 and 1/12 (simplest form/simplified) or 49/12

Answer is 49/12 or 4 and 1/2

:)

6 0

4 years ago

Explain why the formula is not valid for matrices. Illustrate your argument with examples. (A + B)(A − B) = A2 − B2 The formula

julsineya [31]

Answer:

The formula is not valid because the commutative property with respect to the matrix product operation is not fulfilled in the vector space of the real matrices.

Step-by-step explanation:

The formula is not valid because the commutative property with respect to the matrix product operation is not fulfilled in the vector space of the real matrices. That is, AB does not necessarily equal BA.

$(A+B)(A-B) = A^2-AB+BA-B^2\neq A^2 - B^2$

$A=\left[\begin{array}{ccc}1&0&0\\0&0&6\\0&8&0\end{array}\right] \\B=\left[\begin{array}{ccc}0&2&0\\6&0&0\\0&0&9\end{array}\right] \\(A -B) = \left[\begin{array}{ccc}1&-2&0\\-6&0&6\\0&8&-9\end{array}\right]\\\\(A + B) = \left[\begin{array}{ccc}1&2&0\\6&0&6\\0&8&9\end{array}\right]\\(A - B)(A + B) = \left[\begin{array}{ccc}-11&2&-12\\-6&36&54\\48&-72&-33\end{array}\right]\\A^2 - B^2 = \left[\begin{array}{ccc}-11&0&0\\0&36&0\\0&0&-33\end{array}\right]\\$