The vertex is (2, -3).
Use the formula x= -b/2a to find the x value., which is 2.Then, substitute it into the function, wherever you see an x. Follow order operations and you get y, which is -3.
Answer:
Option B
Step-by-step explanation:
Taking the derivative of the residual function, then applying the normal equation:
[a; b] = (X'*X)^(X'*y)
with
X = [1 1; 2 1; 3 1; 4 1; 5 1]
X' is transpose of X
y = [11; 8; 4; 1; 0]
[a; b] = [-2.9 13.5]
<span>1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2
D.y=-x
2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6
C.y=-3/2x+2
3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4
4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1
B.y=-2x-1
5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)
D.y=-1/2x+5/2</span>
Yes you did, congratulations ;-)
