Following are the statements:
1. Main phagocytes in circulation
2. Like eosinophils, they are involved in inflammation and allergic reactions
3. Phagocytic cells that leave circulation and differentiate into macrophages
4. Display no antigen specificity but are active against tumor and virally infected cells
Answer:
1. Neutrophils
2. Basophils
3. Monocytes
4. Natural killer cells
Explanation:
Neutrophils can be described as the most abundant type of white blood cells. They make up to 55%- 75% of the immune system.
Basophils can be described as white blood cells which are made in the bone marrow.
Monocytes can be described as white blood cells which are the largest and differentiate into macrophages and myeloid lineage dendritic cells.
Natural killer cells can be described as white blood cells which play a role in providing innate immunity.
Answer:
It could be carbohydrates, or just food in general
Answer:
Water!
Explanation:
A stream-lined and slippery body is the characteristic feature of aquatic organisms. The stream-lined body of aquatic animals helps them move easily in water. Possessing a streamlined body reduces resistance when moving whereas a slippery body provide resistance to parasites and also help some animals to breathe through their skin.
Hope this helps! :)
This link should help it has all the information you need...
https://arxiv.org/pdf/1511.08792.pdf
Answer:
Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).
Explanation:
<u>Datos disponibles:</u>
- Cruce entre peces naranjas y peces grises
- 50% de la F1 son peces grises
- Naranja dominante sobre gris
Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo para color gris <em>n</em>.
Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.
Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.
Cruce:
Parental) Nn x nn
Gametas) N n n n
Fenotipos) Naranja Gris
Cuadro de Punnett) N n
n Nn nn
n Nn nn
F1) 2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn
2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,
nn
50% de la progenie será color naranja (Nn)
50% de la progenie será color gris (nn)
