RNA polymerase binds to the lac promoter and begins transcribing
the stretch of DNA to messenger RNA.
Therefore, in other words, the stretch of DNA is expressed. The DNA sequence of
the lac promoter 'signals' where the RNA
polymerase will bind and where transcription
will begin. Promoters are found upstream of a gene to be transcribed.
Answer:
1/16
Explanation:
- scalloped (Xsd) is an X-linked recessive trait to Xsd+ (wild type)
- ebony (e) is an autosomal mutation recessive to e+ (wild type).
The two genes are independent because they are located on different chromosomes.
<h3>
<u>Parental generation:</u></h3>
True breeding scalloped female wild type for ebony (<em>Xsd Xsd e+e+</em>) mates with a true breeding male mutant only for ebony (<em>Xsd+ Y ee</em>).
The female only produces <em>Xsd e+</em> gametes. The male produces <em>Xsd+ e</em> or <em>Y e</em> gametes.<u> Therefore, the F1 females will have the genotype </u><u><em>Xsd Xsd+ e e+ </em></u><u>and the F1 males will have the genotype </u><u><em>Xsd Y e e+.</em></u>
If you complete a Punnett Square with the gametes the two F1 individuals can produce, you will get all the F2 proportions. The scalloped, ebony females have a<em> Xsd Xsd e e</em> genotype and appear in a 1/16 proportion.
The type of learning that involves problem-solving is called insight.
Answer: uracil is found in RNA nucleotides, but NOT in DNA, i hope that helps
Explanation: