Question

sandy is upgrading her internet service. Fast internet charges $60 for installation $50.45 per month. Quick internet has free installation but charges $57.95 per month write an equation that can be used to find the number of months for which the internet service would cost the same

Answer 1

In order to know at what price the two services offered would be the same, we can actually use the process of trial and error starting from 1 onwards. The first one is 50.45 per month plus a standard fee of 60 for installation. So this will be 60+50.45x (number of days). After that. there is the other one that has free installation but charges 57.95. So it can be expressed as 57.95x. Now after trial and error with numbers as x, I came upon 8. If x is 8, then the first one will be 60+50.45 (8) = 463.6. For the second, 57.95(8) will also equal to 463.6. So the day in which the two services will charge the same is during the 8th day. 

Answer 2

Answer:

$60+50.45x=57.95x$

Step-by-step explanation:

Given months as $x$,

Cost of Fast Internet:

$60 for installation and $50.45 per month for $x$ months = $60+50.45x$

Cost of Quick Internet:

Free installation and $57.95 per month for $x$ months = $57.95x$

We want to know in how many months BOTH COSTS WOULD BE SAME. So we EQUATE the expressions for both. We have:

$60+50.45x=57.95x$

This equation can be solved for x to find the number of months for which the internet service would cost the same.