1. Observe question
2. Employ Point-Slope formula
(y2 - y1)/(x2 - x1 )=
(-10-9)/(-6-9) =
-19/-15=
19/15
Slope: 19/15
<span>-1/4y(2y^3 - 8)
= -1/2 y^4 + 2 y</span>
TQRS is an inscribed quadrilateral.
5 x - 52° + 3 x + 40° = 180°
8 x - 12° = 180°
8 x = 180° + 12°
8 x = 192°
x = 192° : 8 = 24°
m∠ R = 3 · 24° + 40° = 112°
m∠ T = 5 · 24° - 52° = 68°
m∠ S = 360° - ( 68° + 68° + 112° ) = 112°
Answer:
m∠R, m∠S, m∠T = 112°, 112°, 68°.
Answer:
(1, 6 )
Step-by-step explanation:
5x + 2y = 17 → (1)
4x + y = 10 → (2)
Multiplying (2) by - 2 and adding to (1) will eliminate the y- term
- 8x - 2y = - 20 → (3)
Add (1) and (3) term by term to eliminate y
- 3x + 0 = - 3
- 3x = - 3 ( divide both sides by - 3 )
x = 1
Substitute x = 1 into either of the 2 equations and solve for x
Substituting into (1)
5(1) + 2y = 17
5 + 2y = 17 ( subtract 5 from both sides )
2y = 12 ( divide both sides by 2 )
y = 6
solution is (1, 6 )
