Answer: w = 7, x = 6
Step-by-step explanation: Solve by substitution
W + b = 13
rewrite as b = 13 - w and substitute that value for b in the second equation
6.5w + 2b = 57.5 Then solve for w
6.5w + 2(13-w) = 57.5 . Distribute
6.5w + 26 - 2w = 57.5 . Subtract 26 from both sides. Combine like terms and simplify
6.5w - 2w = 57.5 - 26
4.5w = 31.5 Divide both sides by 4.65
w = 7 . Substitute 7 for w in the first equation and solve for b
7 + b = 13 . Subtract 7 from both sides
b = 6
Let the measure of side AB be x, then, the measue of side AE is given by

.
Now, ABCD is a square of size x, thus the area of square ABCD is given by

Also, AEFG is a square of size

, thus, the area of square AEFG is given by

<span>The sum of the areas of the two squares ABCD and AEFG is given by

Therefore, </span>the number of square units in the sum of the areas of the two squares <span>ABCD and AEFG is 81 square units.</span>
I believe the number of students they had last year are 360 students i hope this helps.
Notice that the reflection is over a line of the form x=constant; in this case, the y-coordinate of the reflected point stays the same while the x-coordinate changes as expressed by the transformation below

Hence, in our case

Transform points N, M, and O accordingly,

<h2>Therefore, the answer is the first option (top to bottom)</h2>
0.9 x 10^4
Let’s break this down into steps.
So to start off with, you need to do 4.5/5 which = 0.9.
Now we can deal with the indices. 10^-3 / 10^-7 means we have to subtract them. Therefore, -3 - -7 = 4. Altogether, we have 0.9 x 10^4
The question states we should leave our answer in standard form.
So our answer is 0.9 x 10^4.