All categories

3 years ago

Which fraction is equal to 6?

Mathematics

1 answer:

Gala2k [10]3 years ago

7 0

Answer:

12/2

Step-by-step explanation:

You might be interested in

System OT<br> W + b =13<br> 6.5w + 2b = 57.5

mixer [17]

Answer: w = 7, x = 6

Step-by-step explanation: Solve by substitution

W + b = 13

rewrite as b = 13 - w and substitute that value for b in the second equation

6.5w + 2b = 57.5 Then solve for w

6.5w + 2(13-w) = 57.5 . Distribute

6.5w + 26 - 2w = 57.5 . Subtract 26 from both sides. Combine like terms and simplify

6.5w - 2w = 57.5 - 26

4.5w = 31.5 Divide both sides by 4.65

w = 7 . Substitute 7 for w in the first equation and solve for b

7 + b = 13 . Subtract 7 from both sides

b = 6

6 0

2 years ago

Angle $eab$ is a right angle, and $be = 9$ units. what is the number of square units in the sum of the areas of the two squares

Alla [95]

Let the measure of side AB be x, then, the measue of side AE is given by

$AE=\sqrt{9^2-x^2}$ .

Now, ABCD is a square of size x, thus the area of square ABCD is given by

$Area=x^2$

Also, AEFG is a square of size $\sqrt{9^2-x^2}$ , thus, the area of square AEFG is given by

$Area=\left(\sqrt{9^2-x^2}\right)^2=9^2-x^2=81-x^2$

<span>The sum of the areas of the two squares ABCD and AEFG is given by

$x^2+81-x^2=81$

Therefore, </span>the number of square units in the sum of the areas of the two squares <span>ABCD and AEFG is 81 square units.</span>

8 0

2 years ago

There are 1800 students in a school this number is 20% more than what they had last year find the number of students in the scho

harkovskaia [24]

I believe the number of students they had last year are 360 students i hope this helps.

5 0

3 years ago

Triangle NMO has vertices at N(−5, 2), M(−2, 1), O(−3 , 3). Determine the vertices of image N′M′O′ if the preimage is reflected

Firdavs [7]

Notice that the reflection is over a line of the form x=constant; in this case, the y-coordinate of the reflected point stays the same while the x-coordinate changes as expressed by the transformation below

$\begin{gathered} y\rightarrow y \\ x\rightarrow2a+x \\ where \\ x=a\rightarrow\text{ vertical line} \end{gathered}$

Hence, in our case

$\Rightarrow(x,y)=(2*-4-x,y)=(-8-x,y)$

Transform points N, M, and O accordingly,

$\begin{gathered} \Rightarrow N^{\prime}=(-8-(-5),2)=(-8+5,2)=(-3,2) \\ \Rightarrow M^{\prime}=(-8-(-2),1)=(-6,1) \\ \Rightarrow O^{\prime}=(-8-(-3),3)=(-5,3) \end{gathered}$ <h2>Therefore, the answer is the first option (top to bottom)</h2>

6 0

11 months ago

Answer in standard form PLEASE.

matrenka [14]

0.9 x 10^4

Let’s break this down into steps.

So to start off with, you need to do 4.5/5 which = 0.9.

Now we can deal with the indices. 10^-3 / 10^-7 means we have to subtract them. Therefore, -3 - -7 = 4. Altogether, we have 0.9 x 10^4

The question states we should leave our answer in standard form.

So our answer is 0.9 x 10^4.

8 0

2 years ago