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kenny6666 [7]
3 years ago
11

What does 1 ft equal to​

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
6 0
Equal in what? Cm, m, mm ?
ikadub [295]3 years ago
5 0

1 ft:

= 30.48 cm

= 0.3048 m

= 304.8 mm

= 0.33 yards

= 12 inches

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Points F(3, 3), K(6, 5), J(8, 2) and L(5, 0) lie in a coordinate plane. Which lines are perpendicular?
Romashka-Z-Leto [24]
To determine if a line is perpendicular to another, you must first determine the slope...
m = y1-y2/x1-x2
m of FK = 3-5/3-6 = -2/-3 = 2/3
m of FJ = 3-2/3-8 = 1/-5
m of FL = 3-0/3-5 = 3/-2
m of KJ = 5-2/6-8 = 3/-2
m of KL = 5-0/6-5 = 5
m of JL = 2-0/ 8-5 = 2/3

In order for two lines to be perpendicular, their slopes must be opposite reciprocals...
FK is perpendicular to FL
FK is perpendicular to KJ
JL is perpendicular to FL
JL is perpendicular to KJ
FJ is perpendicular to KL
8 0
3 years ago
Q.5(b) The population {(P) in millions} of a country is estimated by the function, P=125e0.035t, t = time measured in years sinc
nekit [7.7K]

Answer:

Hello,

Step-by-step explanation:

Q.5(b) The population {(P) in millions} of a country is estimated by the function, P=125e0.035t, t = time measured in years since 1990. (a) what is the population expected to equal in year 2000 (b) determine the expression for the instantaneous rate of change in the population (c) what is the instantaneous rate of change in the population expected to equal in year 2000.

P(t)=125*e^{0.035*t}\\a)\\P(2000)=125*e^{0.035*(2000-1990)}=177.38...\\\\b)\\P'(t)=125*0.035*e^{0.035*t}\\\\c)\\\\P'(2000)=125*0.035*e^{0.035*(2000-1990)}=6.2084...

5 0
3 years ago
What is the answer <br> simplify 2(5x+3)-2(2x-3)
Pavel [41]

Answer:Use this PEMDAS to solve

Step-by-step explanation:

Parethiesis,Exponent,Multiplication,Division,Addition,and Subtraction.

ALWAYS DO P FIRST!!!!

4 0
3 years ago
Read 2 more answers
Which equation describes a line that passes through (-6, 8) and is parallel to the line described by y = 2x − 4?
AleksandrR [38]

Answer:

hey, there!

Step-by-step explanation:

The given is a point (-6,8) through which a line passes. And is perpendicular to the line y = 2x-4

The equation for point (-6,8) is,

(y-8)= m1(x+6)...........(i)

and given equation is y = 2x-4............(ii)

Now, from equation (ii).

slope (m2)= 2 { as equation (ii) is in the form of y= mx+c where m is a slope}.

Now, For perpendicular,

m1×m2= -1

m1×2= -1

Therefore, m1 = -1/2.

Putting, the value of m1 in equation (i).

(y-8) = -1/2×(x+6)

2(y-8)= -1(x+6)

2y - 16 = -x -6

x+2y-10 = 0......... is the required equation.

Hope it helps...

6 0
2 years ago
With a detailed explanation from the internet<br> 1/(x-5)+3/(x+2)=4
irga5000 [103]

Answer:

\boxed{ \sf x=\dfrac{4\pm\sqrt{43}}{2}}

Explanation:

\rightarrow \sf \dfrac{1}{x-5}+\dfrac{3}{x+2}=4

<u>make the denominators same</u>

\rightarrow \sf \dfrac{1(x+2)}{(x-5)(x+2)}+\dfrac{3(x-5)}{(x+2)(x-5)}=4

<u>join the fractions together</u>

\rightarrow \sf \dfrac{x+2+3x-15}{(x-5)(x+2)}=4

<u>cross multiply</u>

\rightarrow \sf x+2+3x-15=4(x-5)(x+2)

<u>simplify</u>

\rightarrow \sf 4x-13=4x^2-12x-40

<u>group the variables</u>

\rightarrow \sf 4x^2-16x-27 = 0

<u>use quadratic formula</u>

\rightarrow \sf x = \dfrac{-\left(-16\right)\pm \sqrt{\left(-16\right)^2-4\cdot \:4\left(-27\right)}}{2\cdot \:4}

<u>simplify the following</u>

\rightarrow \sf x=\dfrac{4\pm\sqrt{43}}{2}

7 0
2 years ago
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