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igor_vitrenko [27]
3 years ago
5

PLEASE SOMEONE HELP!!!!!!!!!!!!!

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
3 0

Answer:

32

Step-by-step explanation:

Substitute p=-2 into the equation and solve.

2|6+p|-3p^3\\2|6+(-2)|-3(-2)^3\\2|4|-3(-8)\\2*4-3(-8)\\8+24\\32

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The quotient of 794.1 divided by 7.61, expressed to two decimal places, is A. 104.35. B. 95.83. C. 786.49. D. 1,043.50.
AysviL [449]
<span>The question asks us to find the quotient of 794.1 by 7.61, expressed to two decimal places. First we will divide those two numbers: 794.1 : 7.61 = 104.34954. Then we have to round the result to the 2 decimal places. After 104.34 is 9 so we have to round the number to 104.35. Answer: The quotient is 104.35.</span>
3 0
3 years ago
If m RDC = 120°, then m DAC=?
monitta
The correct answer to this question is 240

From the image i've seen, the RDC has an angle of 120. So the major arc DC (that passes A and B) has an angle of 240.

So this makes that the measure of the angle of DAC is 240 because of the angle formed by RDC which is 120.
7 0
3 years ago
Read 2 more answers
Please help me quick!!
andrezito [222]

Answer:

B. (52,32)

Step-by-step explanation:

32 = 52 - 20

32 = 32

52 + 32 = 84

84 = 84

6 0
3 years ago
If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.
Sophie [7]
There's no if about it, 

f(x)=x^3+3x^2-x-3&#10;

has a zero f(1)=0 so x-1 is a factor.   That's the special case of the Remainder Theorem; since f(1)=0 we'll get a remainder of zero when we divide f(x) by x-1.

At this point we can just divide or we can try more little numbers in the function.  It doesn't take too long to discover f(-1)=0 too, so  x+1 is a factor too by the remainder theorem.  I can find the third zero as well; but let's say that's out of range for most folks.

So far we have 

x^3+3x^2-x-3 = (x-1)(x+1)(x-r)

where r is the zero we haven't guessed yet.  Again we could divide f(x) by (x-1)(x+1)=x^2-1 but just looking at the constant term we must have

-3 = -1 (1)(-r) = r

so

x^3+3x^2-x-3 = (x-1)(x+1)(x+3)

We check f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark

We usually talk about the zeros of a function and the roots of an equation; here we have a function f(x) whose zeros are

x=1, x=-1, x=-3

8 0
3 years ago
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Find the arc length of a central angle of 7pi/3 in a circle whose radius is 3 inches.
skelet666 [1.2K]

\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ \hrulefill\\ r=3\\ \theta =\frac{7\pi }{3} \end{cases}\implies s=3\cdot \cfrac{7\pi }{3}\implies s=7\pi

4 0
3 years ago
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