Answer:
it must also have the root : - 6i
Step-by-step explanation:
If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.
This is because in order to render a polynomial with Real coefficients, the binomial factor (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:
where the imaginary unit has disappeared, making the expression real.
So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)
Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.
Answer:
dee y by dee x
Step-by-step explanation: hope this helps! have a supercalifragilisticexpialidocious day! ◑﹏◐
Answer:
The answer is A. pi=pf
Step-by-step explanation:
Just took the test
Answer:
<h3>
The percentage is <u>
60%</u>
of the total amount paid with the gift card. </h3>
Step-by-step explanation:
Given:
Total worth of clothing is $178.25 and the amount paid with cash is $71.30.
Let us find the part of amount paid with the gift card:
Amount of gift card(G) = Total worth(T) - Amount paid in cash(C).

.
So, the amount paid with the gift card is $106.95.
Now, according to question:


%.
Therefore, the percentage is <u>60%</u> of the total amount paid with the gift card.