.50 repeating as a fraction
1 answer:
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Answer:
This is a radioactive decay / half-life problem.
Initial amount of C 14 = 100% Present Amount = 57%
k = .0001 (that value should be negative)
Nt = No * e^ (k*t)
You need to solve that equation for "time" (equation attached)
time = natural log (Ending amount / Starting Amount) / k
time = natural log (57% / 100%) / -.0001
time = ln (.57) / -.0001
time = -.56211891815 / -.0001
time = 5,621.2 years (age of the bird skeleton)
These problems are quite complicated but I think I know this pretty well.
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Step-by-step explanation:
-8, -19, -30, -49 , -60
<u>Step-by-step explanation:</u>
Here we have the following sequence :
-8, -19, -30, _ , _
- First term of sequence is -8 .
- Second term of sequence is -19 :
- Third term of sequence is -30 :
- Fourth term of sequence is :
- Fifth term of sequence is :
Following sequence was an AP( Arithmetic Progression ) with first term as -8 i.e. and common difference
having general equation as :
.