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Ber [7]
4 years ago
13

What is a location in between an electrical generating plant and consumers that changes the voltage of the electricity from high

to low using transformers?
Physics
2 answers:
elena55 [62]4 years ago
8 0
From the generating "base" to the user the change in the high to low frequency depends on range from in between the two and is changed by a electric power transmission, which is the bulk movement of electrical energy from a generating site, such as a power plant, to an electrical substation.
katrin2010 [14]4 years ago
4 0
<span>Between the generating station and consumer, electric power may flow through several substations at different voltage levels. that it </span>
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With a bit of algebraic reasoning find your gravitational acceleration toward any planet of mass M a distance d from its center.
grandymaker [24]

The acceleration due to gravity is given as:

                             g = GM/r²

<h3>Derivation of gravitational acceleration:</h3>

According to Newton's second law of motion,

F = ma

where,

F = force

m = mass

a = acceleration

According to Newton's law of gravity,

F<em>g </em>= GMm/(r + h)²

F<em>g = </em>gravitational force

From Newton's second law of motion,

F<em>g </em>= ma

a = F<em>g</em>/m

We can refer to "a" as "g"

a = g = GMm/(m)(r + h)²

g = GM/(r + h)²

When the object is on or close to the surface, the value of g is constant and height has no considerable impact. Hence, it can be written as,

g = GM/r²

Learn more about gravitational acceleration here:

brainly.com/question/2142879

#SPJ4

5 0
2 years ago
Discuss impact of Newton's second law on roads​
ruslelena [56]

Answer:

The second law: When a force is applied to a car, the change in motion is proportional to the force divided by the mass of the car. This law is expressed by the famous equation F = ma, where F is a force, m is the mass of the car, and a is the acceleration, or change in motion, of the car

4 0
3 years ago
Astronomers have found water on mars.
vodomira [7]

The thin atmosphere of Mars is thought to be due to the planet's lack of a magnetic field, which has allowed the Solar wind to blow away much of the gas the planet once had. Venus, despite still having a thick atmosphere of CO2, surprisingly has a similar problem

4 0
2 years ago
A convex security mirror has a radius of curvature of 12.0 cm. What is the magnification of a pare 3.0 m from the mirror?
Makovka662 [10]

Answer:

magnification will be -0.025

Explanation:

We have given the radius of curvature = 12 cm

And object distance = 3 m

So focal length f=\frac{R}{2}=\frac{12}{2}=6cm

Now for mirror we know that \frac{1}{f}=\frac{1}{u}+\frac{1}{v}

So \frac{1}{0.06}=\frac{1}{3}+\frac{1}{v}

16.66-0.333=\frac{1}{v}

v = 0.750 m

Now magnification of the mirror is m=\frac{-v}{u}=\frac{-0.750}{3}=-0.025

5 0
4 years ago
An observer sees a full moon in the night sky. What will the Moon's phase be 10 days later?
algol [13]
I'm pretty sure the moon would be a crescent within the 10 day period because it takes about 28 days for the moon to go through the different stages.
5 0
4 years ago
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