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NISA [10]
3 years ago
13

Which type of galaxy has arms that contain sites of active star formation and start close to a bulge in the center?

Physics
2 answers:
Sergeeva-Olga [200]3 years ago
8 0
Barred spiral is correct answer
Serhud [2]3 years ago
5 0

Answer:

normal spiral I think. I hope this helps

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HELP PLEASE!! An illustration of a pendulum at 3 positions of a pendulum. The equilibrium position is labeled B. The other two p
Sedbober [7]

Answer:

Both A and C

Explanation:

I just got it correct on Edg

7 0
3 years ago
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Give me fun facts, the most fun fact will get brainly Est (i like animals)
swat32

Answer:

here are some fun facts lol

Dolphins sleep with one eye open

Hot water will turn into ice faster than cold water.

A crocodile cannot stick its tongue out

It is physically impossible for pigs to look up into the sky

Grapes light on fire in the microwave

McDonald's once created bubblegum-flavored broccoli.

It's impossible to sneeze with your eyes open.

High Heels Were Originally Men's Shoes

The strongest muscle in the body is the tongue.

While they are hibernating, bears do not urinate

Gummy bears were originally called "dancing bears."

Explanation:

3 0
2 years ago
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At the same moment, one rock is dropped and one is thrown downward with an initial velocity of 29m/s from the top of a building
Inessa [10]

Answer:

The thrown rock strike 2.42 seconds earlier.

Explanation:

This is an uniformly accelerated motion problem, so in order to find the arrival time we will use the following formula:

x=vo*t+\frac{1}{2} a*t^2\\where\\x=distance\\vo=initial velocity\\a=acceleration

So now we have an equation and unkown value.

for the thrown rock

\frac{1}{2}(9.8)*t^2+29*t-300=0

for the dropped rock

\frac{1}{2}(9.8)*t^2+0*t-300=0

solving both equation with the quadratic formula:

\frac{-b\±\sqrt{b^2-4*a*c} }{2*a}

we have:

the thrown rock arrives on t=5.4 sec

the dropped rock arrives on t=7.82 sec

so the thrown rock arrives 2.42 seconds earlier (7.82-5.4=2.42)

6 0
3 years ago
A charge of -8.5 µC is traveling at a speed of 9.0 106 m/s in a region of space where there is a magnetic field. The angle betwe
Sindrei [870]

Answer:

The magnitude of the magnetic field is 9.3\times 10^{-5}\ T.

Explanation:

Given that,

Charge, q=-8.5\ \mu C=-8.5\times 10^{-6}\ C

Speed of the charged particle, v=9\times 10^6\ m/s

The angle between the velocity of the charge and the field is 56°.

The magnitude of force, F=5.9\times 10^{-3}\ N

We need to find the magnitude of the magnetic field. When a charged particle moves in the magnetic field, the magnetic force is experienced by it. The force is given by :

F=qvB\ \sin\theta

B is the magnetic field.

B=\dfrac{F}{qv\ \sin\theta}\\\\B=\dfrac{5.9\times 10^{-3}}{8.5\times 10^{-6}\times 9\times 10^6\ \sin(56)}\\\\B=9.3\times 10^{-5}\ T

So, the magnitude of the magnetic field is 9.3\times 10^{-5}\ T. Hence, this is the required solution.

4 0
3 years ago
A sprinter who is running a 200-m race travels the second 100 m in much less time than the first 100m because
Harrizon [31]

Answer:

He is warmed up now

Explanation:

His muscles are better and stretched now

3 0
3 years ago
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