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Ahat [919]
3 years ago
9

Last week Kiwi filled his 16-gallon tank with gas. On the average, his car burns 0.03 gallon of gas per mile. If Kiwi has 4 gall

ons left in his tank, how many miles has he driven?
Mathematics
2 answers:
Evgen [1.6K]3 years ago
8 0

Answer: 400 Miles


Step-by-step explanation:

Okay to find the answer you must use how many gallons he has already used which is 12 Gallons.


They say the average is 0.03 Gallons per Mile.


You divide 12/0.03 to get 400 Miles. (:

Alex777 [14]3 years ago
4 0

Answer:

He has driven 400 miles.

Step-by-step explanation:

Total amount of gas = 16 gallons

Amount of gas left= 4 gallons

Amount of gas used = 16-4 = 12 gallons

No. of miles traveled in 0.03 gallons of gas = 1

No. of miles traveled in 1 gallon of gas = \frac{1}{0.03}

No. of miles traveled in 12 gallon of gas = \frac{1}{0.03} \times 12

                                                                  = 400

Hence he has driven 400 miles.

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Roll one fair, six-sided die, numbered 1 through 6. Let A be the event you will roll an even number. Let B be the event you will
11111nata11111 [884]

Answer:

a) not independent

b) not mutually exclusive

Step-by-step explanation:

Given:

- A 6 sided die is rolled

- Event A is rolling an even number

- Event B is rolling a prime number

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- (b) Are A and B mutually exclusive events?

Solution:

- We will find the probability of each event:

                       set(Even number: A) = {2, 4, 6} = 3 outcomes

                       set(Prime number: B) = {2 , 3, 5} = 3 outcomes

- The probabilities are:

                        P(A) = 3/6 = 0.5

                        P(B) = 3/6 = 0.5

- For Event A and B to be independent then the following condition must match:

                        P ( A & B ) = P(A)*P(B)

                        set (A&B) = {2} = 1 outcome

                        P(A&B) = 1/6

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- For Event A and B to be mutually exclusive then the following condition must match:

                        P(A&B) = 0

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The distance d of a particle moving in a straight line is given by d(t) = 2t3 + 5t – 2, where t is given in seconds and d is mea
Sergeeva-Olga [200]

Answer:

(C)6t^2+5

Step-by-step explanation:

Given the distance, d(t) of a particle moving in a straight line at any time t is:

d(t) = 2t^3 + 5t - 2, $ where t is given in seconds and d is measured in meters.

To find an expression for the instantaneous velocity v(t) of the particle at any given point in time, we take the derivative of d(t).

v(t)=\dfrac{d}{dt}\\\\v(t) =\dfrac{d}{dt}(2t^3 + 5t - 2) =3(2)t^{3-1}+5t^{1-1}\\\\v(t)=6t^2+5

The correct option is C.

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