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3 years ago

Rewrite the expression with the given base. 125^2x with a base of 5

Mathematics

2 answers:

Firdavs [7]3 years ago

8 0

Note that 125 = 5^3

So 125^2x = 5^3(2x) = 5^6x answer

jasenka [17]3 years ago

6 0

Okay so you have to start by working out how many times you multiply 5 by itself to get 125.

5x5x5=125

therefore: (5^3)^2x) is the answer:)

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Answer:

First, let's move all terms to one side,

$\sf x^2-8x+6=0$

When given this form (ax^2+bx+c=0), there will be two solutions at the end.

1) $\sf x=\frac{-b+\sqrt{b^2-4ab} }{2b}$

2) $\sf x=\frac{-b-\sqrt{b^2-4ab} }{2b}$

where, a=1, b=-8, c=6

$\sf x=\frac{8+\sqrt{(-8)^2-4\times6} }{2} ,\frac{8-\sqrt{(-8)^2-4\times6} }{2}$

Simplify,

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Simplify,

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3 years ago

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3 years ago

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Answer:

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