All categories

3 years ago

Where will these 2 lines intersect? y = 2x + 7 and x = y + 4

Mathematics

2 answers:

Vladimir79 [104]3 years ago

8 0

To find the intersecting point, you have to put the two formulas equal to each other

First isolate the same variable, in this case y

So y=x-4

Now we can say

2x + 7 = x - 4

Now solve for x

X= 3

Now fill this in in either one of the formulas

Y= 2 (3) + 7

Y= 13

So they’ll intersect at (3,13)

defon3 years ago

5 0

To find the intersecting point, you have to put the two formulas equal to each other
First isolate the same variable, in this case y
So y=x-4

Now we can say
2x + 7 = x - 4

Now solve for x

X= 3

Now fill this in in either one of the formulas

Y= 2 (3) + 7
Y= 13

So they’ll intersect at (3,13)

You might be interested in

Norton can mow the large lawn in about 5 hours. When he works with

astra-53 [7]

Answer:

7.5 hours

Step-by-step explanation:

The key here is to find out how much can be done in the same amount ot time

the least common multiple of 5 hrs and 3 hrs is 15hrs

In 15 hours:

- At 5 hours per lawn Norton could mow 15/5 = 3 lawns

- At 3 hours per lawn together thay could mow 15/3 = 5 lawns

In 15 hours Jesse would mow 5 - 3 = 2 lawns

15 hours/ 2 lawns = 7.5 hours per lawn

7.5 hours

--------------------

Here's the math

1 lawn/5hrs + x = 1 lawn / 3hrs

1/5 + x = 1/3

Subtract 1/5 from both sides

x = 1/3 - 1/5

x = 5/15 - 3/15

x = 2/15

x = 2lawns/15 hrs

15hrs/2lawns = 7.5 hrs per lawn

7.5 hours

5 0

3 years ago

A rectangular lawn, 100 feet long by 50 feet wide, is to have two sidewalks installed that will cut the lawn in half both ways,

Damm [24]

Answer:

3.41 feet

Step-by-step explanation:

Area = Length × Breath

Area of the rectangular lawn = 100 × 50

= 5000 feet²

The sidewalk must occupy an area no more than 10% of the total lawn area.

So, the area of the sidewalk would be not more than = 10% × 5000

= 0.10 × 5000

= 500 feet²

Let the width of the sidewalk = x feet

area of the side walk = (L×W of the long way) + ((L-x)×W of the short way)

(100 × x) + ((50 - x) × x) < 500

100x + (50-x)(x) < 500

-x² + 150x < 500

-x² + 150x = 500

-x² + 150x - 500 = 0

By using quadratic formula

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

$x=\frac{(-150)\pm\sqrt{(150)^2-4(-1)(-500)} }{2(-1)}$

$x=\frac{-150\pm \sqrt{20500} }{-2}$

$x=75-5\sqrt{205}$ or $x=75+5\sqrt{205}$

x = 3.41089 ≈ 3.41 feet or x = 146.58

Therefore, width of the sidewalk would be 3.41 feet.

5 0

3 years ago

Find the volume of a right circular cone that has a height of 15.2 m and a base with a radius of 16.2.Round your answer to the n

AURORKA [14]

Answer:V≈4177.36m³

Step-by-step explanation:

4 0

3 years ago

One number is ten times another number. Their sum is 253.

s344n2d4d5 [400]

Answer:

23,230

Step-by-step explanation:

230 is ten times larger than 23, and if you add them together is it 253

5 0

3 years ago

1/4 diveided bye 9/10

Gnom [1K]

The answer is 1/360

8 0

2 years ago

Read 2 more answers