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nika2105 [10]
3 years ago
14

Solve for “x” to the nearest tenth. (Hint: Find a decimal that, when multiplied by itself, will be approximately 46.)

Mathematics
1 answer:
abruzzese [7]3 years ago
5 0

Answer:

<h2>6.79</h2>

Step-by-step explanation:

According to Question,

{x}^{2}  = 46

Squaring on both sides

\sqrt{ {x}^{2} }  =  \sqrt{46}

Calculate

x = 6.79

Let's check :

If we multiply 6.79 by itself, then the result will be approximately 46.

Hope this helps..

Best regards!!

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Please i need your help
Sloan [31]

Answer: 475 Add 5 more.

Step-by-step explanation:

7 0
2 years ago
If the rate 130 miles per 2 hours is reduced to a unit rate, the result is
sammy [17]

Answer:

65 miles every 1 hour

Step-by-step explanation:

Unit rate is found once one of the units is 1. In this case we need to reduce the ratio so that it is 1 hour and we get a unit rate. We can do this by dividing both sided by 2 so that the hours are reduced to 1.

130=2

130/2=65                2/2=1

65=1

65 miles every hour

3 0
3 years ago
How to do this question
slava [35]

Answer:

Length of the shorter diagonal is 8.68 cm.

Step-by-step explanation:

Length of the side AB = 11 cm

Length of side BC = 5 cm

Angle between these sides, m∠ABC = 50°

By cosine rule in ΔABC,

AC² = AB² + BC² - 2AB.BC.cos B

AC² = (11)² + 5² - 2(11)(5)cos50°

AC² = 121 + 25 - 70.71

AC = √(75.29)

AC = 8.68 cm

By the property of parallelogram,

m∠B + m∠C = 180° [Interior consecutive angles]

50° + m∠C = 180°

m∠C = 130°

Similarly, In ΔBCD,

BD² = BC² + CD² - 2BC.CD.cos130°

BD² = (5)² + (11)² - 2(5)(11)cos130°

BD² = 25 + 121 + 70.71

BD² = 216.71

BD = 14.72 cm

Therefore, length of the shorter diagonal will be 14.72 cm.

7 0
3 years ago
The​ quality-control manager at a compact fluorescent light bulb​ (CFL) factory needs to determine whether the mean life of a la
stira [4]
<h2>Answer with explanation:-</h2>

Let \mu be the population mean .

By observing the given information, we have :-

H_0:\mu=7450\\\\H_a:\mu\neq7450

Since the alternative hypotheses is two tailed so the test is a two-tailed test.

We assume that the  life of a large shipment of CFLs is normally distributed.

(a) Given : Sample size :  n=81 , since n>30 so we use z-test.

Sample mean : \overline{x}=7240

Standard deviation : \sigma=1350

Test statistic for population mean :-

z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

\Rightarrow\ z=\dfrac{7240-7450}{\dfrac{1350}{\sqrt{81}}}\\\\\Rightarrow\ z=-1.4

The critical value (two-tailed) corresponds to the given significance level :-

z_{\alpha/2}=z_{0.025}=1.96

Since the observed value of z (-1.4) is less than the critical value (1.96) , so we do not reject the null hypothesis.

Hence, we conclude that we have enough evidence to accept that the mean life is different from 7450 hours .

(b) The p-value : 2P(z>-1.4)=0.1615 , it means that the probability that the life of CFLs less than 7240 and greater than 7240 is 0.1615.

(c) The confidence interval for population mean is given by :-

\overline{x} \pm\ z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}\\\\=7240\pm(1.96)\dfrac{1350}{\sqrt{81}}\\\\=7240\pm294\\\\=(6946,7534)

,

8 0
3 years ago
Please help me. Ion understand.
larisa86 [58]

Answer:

C

Step-by-step explanation:

use SOH-CAH-TOA

sine= opposite/hypotenuse

cosine=adjacent/hypotenuse

tangent= opp./adj.

so that mean <JMK= 3/6 = 1/2

4 0
3 years ago
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