Question

Solve for “x” to the nearest tenth. (Hint: Find a decimal that, when multiplied by itself, will be approximately 46.)

Answer 1

Answer:

6.79

Step-by-step explanation:

According to Question,

${x}^{2} = 46$

Squaring on both sides

$\sqrt{ {x}^{2} } = \sqrt{46}$

Calculate

$x = 6.79$

Let's check :

If we multiply 6.79 by itself, then the result will be approximately 46.

Hope this helps..

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