Answer:
The outer circle is 16 feet larger than the inner circle (68 - 52).
Step-by-step explanation:
Given that the inner circle circumference is 52 feet, and the distance between the inner and the outer circle is 8 feet, to determine by how many ft is the larger outer circle, the following calculation must be performed:
The radius of a circle is equal to half its diameter. Therefore, the radius of the inner circle is 26 feet. Thus, if the distance between the two circles is 8 feet, the radius of the outer circle is 34 feet (26 + 8). Therefore, the diameter of this circle is 68 feet (34 x 2).
This implies that the outer circle is 16 feet larger than the inner circle (68 - 52).
a)0.43^5*0.57^5
b)0.43^6*0.57^4
c)0.43^3*0.57^7+0.43^2*0.57^8+0.43^1*0.57^9+0.57^10
Answer:
28
Step-by-step explanation:
56/2 = 38
Answer:
Huh I am confused
Step-by-step explanation:
Do you need help with anything
43.305 or in Mixed Number is 43 61/200 or in improper Fraction is 8661/200
