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wlad13 [49]
3 years ago
5

Denise and Jacqueline are training for a swimming and running race.

Mathematics
1 answer:
bezimeni [28]3 years ago
5 0

Answer:

Jacqueline runs at 6.25 minutes per mile

Step-by-step explanation:

Here we have that the total training time for Jacqueline = 54 minutes

The time for which Jacqueline swims = 30 minutes

Therefore, the time in which Jacqueline runs = 54 min. - 30 min. = 20 minutes

Therefore the equation for Jacqueline's speed = Distance/Time we have

Jacqueline's pace = 3.2 miles/20 minutes = 0.16 miles/minute

Therefore Jacqueline's pace = 0.16 miles/minute

The equation for Jacqueline's pace in miles/minute is presented as follows

Jacqueline's pace in miles/minute = Time of running/Distance

Jacqueline's pace in miles/minute  = 1/0.16 miles/minute = 6.25 minutes/mile.

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Answer:

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3 years ago
A number increased by 5 is less than or equal to 26
blagie [28]

Answer:

Equation: x + 5 ≤ 26

Solved: x ≤ 21

3 0
3 years ago
Lucy took out a $15,000 to buy her new car. The bank charged her 8% simple interest rate for the term of 5 years. What is the en
MA_775_DIABLO [31]

Answer:

<h2>$21000</h2>

Step-by-step explanation:

This problem is on simple interest calcultion

A=P(1+r*n)

 where

A=accumulated amount (final)

P= principal amount (initial), $15,000

r=interest written as decimal, 8% = 8/100= 0.08

n=number of years, 5years

Substituting into the expression we have

A=15000(1+0.08*5)

A= 15000(1+0.4)

A=15000(1.4)

A=$21000

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5 0
3 years ago
Use the value of the first integral I to evaluate the two given integrals. I = integral^3_0 (x^3 - 4x)dx = 9/4 A. integral^3_0 (
Troyanec [42]

Answer:

A) -9/2

B) 9/4

C) -9/2, same as A)

Step-by-step explanation:

We are given that I=\int_0^3 x^3-4x dx=9/4. We use the properties of integrals to write the new integrals in terms of I.

A) \int_0^3 8x-2x^3 dx=\int_0^3 -2(x^3-4x) dx=-2\int_0^3 x^3-4x dx=-2I=-9/2. We have used that ∫cf dx=c∫f dx.

B) \int_3^0 4x - x^3 dx=-\int_0^3 (4x-x^3) dx=\int_0^3-(4x-x^3) dx=\int_0^3 x^3-4x dx=I=9/4. Here we used that reversing the limits of integration changes the sign of the integral.

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4 0
3 years ago
100 points!!! Please full out all of these ASAP!!! Please show work!!!
Alex

Answer:

look below

Step-by-step explanation:

y = 2 (x + 3)^2 - 2

Geometric figure:  parabola

Alternate forms:

y = 2 (x + 2) (x + 4)

y = 2 (x^2 + 6 x + 8)

-2 x^2 - 12 x + y - 16 = 0

Expanded form:

y = 2 x^2 + 12 x + 16

Roots:

x = -4

x = -2

<u>Properties as a real function: </u>

Domain - R (all real numbers)

Range - {y element R : y>=-2}

Partial derivatives:

d/dx(2 (x + 3)^2 - 2) = 4 (x + 3)

d/dy(2 (x + 3)^2 - 2) = 0

Implicit derivatives:

(dx(y))/(dy) = 1/(12 + 4 x)

(dy(x))/(dx) = 4 (3 + x)

Global minimum:

min{2 (x + 3)^2 - 2} = -2 at x = -3

3 0
4 years ago
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