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azamat
3 years ago
12

Which matrix will always give a determinant of 0?

Mathematics
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

It's D, a matrix having two equal rows

Step-by-step explanation:

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Justify 2.010010001.....is an irrational number
ser-zykov [4K]
No its rational....................

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4 years ago
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A psychologist wants to estimate the proportion of people in a population with IQ scores between 80 and 140. The IQ scores of th
ryzh [129]

Using the Empirical Rule, it is found that the proportion of people in a population with IQ scores between 80 and 140 is of 0.95 = 95%.

<h3>What does the Empirical Rule state?</h3>

It states that, for a normally distributed random variable:

  • Approximately 68% of the measures are within 1 standard deviation of the mean.
  • Approximately 95% of the measures are within 2 standard deviations of  the mean.
  • Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Considering the mean of 110 and the standard deviation of 15, we have that:

  • 80 = 110 - 2 x 15.
  • 140 = 110 + 2 x 15.

These values are both the most extreme within 2 standard deviations of the mean, hence the proportion of people in a population with IQ scores between 80 and 140 is of 0.95 = 95%.

More can be learned about the Empirical Rule at brainly.com/question/24537145

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7 0
2 years ago
Helppp!!!!! 2 questions answer both
yKpoI14uk [10]
1. The answer would be about 20.72, or 20.7142 if you don’t want the rounded version

2. The answer is -12.8
3 0
3 years ago
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F(x) = (x - 3)(x + 4)
Vladimir [108]

Answer:

f(x)= x^2+x-12

Step-by-step explanation:

FOIL

First= (x)(x)=x^2

Outer=(x)(4)=4x

Inner=(-3)(x)=-3x

Last=(-3)(4)=-12

x^2+4x-3x-12

x^2+x-12

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3 years ago
Why will percent of change always be represented by a positive number?
Murljashka [212]
Percent of change will always be positive because the change is an absolute value. As we know, absolute value is always a positive value because you don't pay attention to the direction, only the distance is important. 
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3 years ago
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