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Marysya12 [62]
3 years ago
7

Turn this into a question

Mathematics
1 answer:
Georgia [21]3 years ago
6 0
How would one control awareness in a "wired brain?"

or

How would awareness in a "wired brain" be controlled?

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The blue segment below is a diameter of O. What is the length of the radius of the circle?
svlad2 [7]
Diameter= 2 times the radius

2r=d
2r=10.2
R= 10.2/2
R=5.1

Therefore, the radius is 5.1 units which makes the answer choice C correct.

Hopefully, this helps!
5 0
3 years ago
Read 2 more answers
Find the Fourier series of f on the given interval. f(x) = 1, ?7 < x < 0 1 + x, 0 ? x < 7
Zolol [24]
f(x)=\begin{cases}1&\text{for }-7

The Fourier series expansion of f(x) is given by

\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi x}7+\sum_{n\ge1}b_n\sin\frac{n\pi x}7

where we have

a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx
a_0=\displaystyle\frac17\left(\int_{-7}^0\mathrm dx+\int_0^7(1+x)\,\mathrm dx\right)
a_0=\dfrac{7+\frac{63}2}7=\dfrac{11}2

The coefficients of the cosine series are

a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx
a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)
a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}
a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}

When n is even, the numerator vanishes, so we consider odd n, i.e. n=2k-1 for k\in\mathbb N, leaving us with

a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}

Meanwhile, the coefficients of the sine series are given by

b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx
b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)
b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}
b_n=\dfrac{7(-1)^{n+1}}{n\pi}

So the Fourier series expansion for f(x) is

f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7
3 0
2 years ago
Im stuck on this question, Please help!
Alexxx [7]
= (x^18y^24)/(x^2y^2)

Simplified = x^16y^22

The last answer is correct (x^16y^22)
3 0
2 years ago
Whats the solution for 9+4n -79 PLEASE ANSWER
iogann1982 [59]

Answer:

I think this is the correct solution

8 0
3 years ago
Write the general polynomial p(x) if its only zeros are 1 4 and -3 with multiplicites 3 2 and 1 respectively what is the degree
kompoz [17]

Answer:

The 6th degree polynomial is p(x) = (x-1)^3(x-4)^2(x+3)

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots x_{1}, x_{2}, x_{n} such that it can be written as: a(x - x_{1})*(x - x_{2})*...*(x-x_n), in which a is the leading coefficient.

Zero 1 with multiplicity 3.

So

p(x) = (x-1)^3

Zero 4 with multiplicity 2.

Considering also the zero 1 with multiplicity 3.

p(x) = (x-1)^3(x-4)^2

Zero -3 with multiplicity 1:

Considering the previous zeros:

p(x) = (x-1)^3(x-4)^2(x-(-3)) = (x-1)^3(x-4)^2(x+3)

Degree is the multiplication of the multiplicities of the zeros. So

3*2*1 = 6

The 6th degree polynomial is p(x) = (x-1)^3(x-4)^2(x+3)

8 0
3 years ago
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