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stira [4]
3 years ago
7

The table lists how financial aid income cutoffs (in dollars) for a family of four have changed over time. Use the midpoint form

ula to approximate the financial aid cutoff for 1985.
Year. Income
1960. 21,250
1970. 27,500
1980. 33,750
1990. 40,000
2000. 46,250
Mathematics
2 answers:
crimeas [40]3 years ago
4 0

Answer:

is go listen to high fashion

Step-by-step explanation:

5t6 67nn jfuuk

Kipish [7]3 years ago
3 0
You can see that every decade the income increases by 6,250. So if you want to do 5 years instead you would have to add 3,125 to the income of 1980 to find what the income was for 1985. Now you add 33,750+3,125= 36,875. The financial aid cutoff for 1985 would be $36,875.
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The perimeter of a rectangle is equal to 40. If the length is halved and the width is divided by 3, the new perimeter is decreas
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Step-by-step explanation:

<em>   M = Original perimeter = 40</em>

<em>    M = 2 w + 2 l = 2 ( w + l )</em>

<em>           40 = 2 ( w + l )</em>

Divide both sides by 2 (simplify)

<em>                20 = w + l</em>

<em>                w + l = 20</em>

Subtract w from both sides

<em>        w + l - w = 20 - w</em>

<em>             l = 20 - w</em>

If the length is halved and the width is divided by 3 mean:

          <em>New length l1 = l / 2 = ( 20 - w ) / 2 = 10 - w / 2</em>

<em>                       New width w1 = w / 3</em>

The new perimeter is decreased by 24 mean:

        <em> P1 = New perimeter = 40 - 24 = 16</em>

<em>             P1 = 2 w1 + 2 l1 = 2 ( w1 + l1 )</em>

<em>                    16 = 2 ( w1 + l1 )</em>

Divide both sides by 2

           8 = w1 + l1

            w1 + l1 = 8

             w / 3 + 10 - w / 2 = 8

 Subtract 10 to both sides

           w / 3 + 10 - w / 2 - 10 = 8 - 10

             w / 3 - w / 2 = - 2

               2 w / 6 - 3 w / 6 = - 2

                 - w / 6 = - 2

Multiply both sides by - 6

       ( - 6 ) ∙ ( - w / 6 ) = ( - 2 ) ∙ ( - 6 )

                w = 12

                   l = 20 - w = 20 - 12 = 8

Proof:

Original perimeter:

        <em>P = 2 w + 2 l = 2 ( w + l ) = 2 ∙ ( 12 + 8 ) = 2 ∙ 20 = 40</em>

New length:

       <em>l1 = l / 2 = 8 / 2 = 4</em>

New width:

        <em>w1 = w / 3 = 12 / 3 = 4</em>

New rectangle will be the square. ( the square is a special case of the rectangle )

New perimeter:

      <em>P1 = 2 w1 + 2 l1 = 2 ( 4 + 4 ) = 2 ∙ 8 = 16</em>

The length of the original rectangle:

                                <u>l = 8</u>

                            <u>Answer 2</u>

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3 years ago
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