Ask question

Ask question

All categories

3 years ago

11

You ride a bicycle at a speed of 18 miles per hour. I am 3 miles behind my friend. My friend rides a bicycle at a speed of 12 mi

les per hour. How long does it take to reach your friend?

1 answer:

anzhelika [568]3 years ago

3 0

Answer:

i think 9 but 6 could also be right

Step-by-step explanation:

18-12=6------18-3=15-------15-3=12-----------12-3=9

You might be interested in

Which number is composite?

Ket [755]

Answer:

Composite numbers are 4, 6, 8 and 9, Then, there is also 10 and 12 in line. They have atleast 3 factors on the shelf, Including the numbers 1 and itself!

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the y-intercept of f–1(x)?

wolverine [178]

Answer:

-16

Step-by-step explanation:

The given linear function is ; $f(x)=\frac{3}{4}x+12$

Let $y=\frac{3}{4}x+12$ .

We interchange x and y.

$x=\frac{3}{4}y+12$ .

We solve for y.

$x-12=\frac{3}{4}y$ .

We now multiply through by $\frac{4}{3}$ to get:

$\frac{4}{3}x-12\times\frac{4}{3}=y$ .

This simplifies to;

$y=\frac{4}{3}x-16$ .

Hence $f^{-1}(x)=\frac{4}{3}x-16$ .

The y-intercept is -16

8 0

3 years ago

A group of workers can plant 27 acres in 9 days. what is there rate in acres per day?

lora16 [44]

Simple 27÷9=3 acres per day

7 0

3 years ago

Samuel bought a cement mixer for $54,205. The value of the cement mixer depreciated at a constant rate per year. The table shows

Paul [167]

The value of cement mixer after t year is $f(t) = 54,205(0. 87)^{t}$

Given to us

The value of cement mixer when bought, $P$ = $ 54,205

the value of cement mixer after 1 year, $P_1$ = $ 47,158. 35

the value of cement mixer after 2 year, $P_2$ = $ 41,027. 76

To find out depreciation we can use the formula for depreciation,

$P_n= P(1-r)^n\\where,\\P_n= Value\ of\ asset\ after\ n\ year\\P= Value\ of\ asset\ when\ bought\\r= rate\ of\ depreciation\\n= number\ of\ years$

By putting the value, in the formula we get,

$P_1= P(1-r)^n\\\\47,158.35= 54,205\times (1-r)^1\\\\\dfrac{47,158.35}{54,205} = (1-r)\\\\0.87=1-r\\\\r=0.13$

Therefore, putting the value of $r$ and $P$ in depreciation formula for $t$ years we get,

$P_n= P(1-r)^n$

$f(t) = 54,205(0. 87)^{t}$

Hence, the value of cement mixer after t year is $f(t) = 54,205(0. 87)^{t}$ .

To know more visit:

brainly.com/question/3023490

8 0

2 years ago

Joe is using the function E= 1.89x + 2.89y to minimize his expenses when selling

stepan [7]

Answer:

$(d)\ \$13.34$

Step-by-step explanation:

Given

$E = 1.89x + 2.89y$ -- Objective function

Constraints:

$2x + y > 10$

$x + 2y > 8$

$x,y>0$

Required

Minimum value of E

To do this, we apply graphical method

See attachment for plots of $2x + y > 10$ and $x + 2y > 8$

From the attached plot, the point that satisfy $x,y>0$ is:

$(x,y) = (4,2)$

So, we have:

$E = 1.89x + 2.89y$

This gives:

$E =1.89 * 4 + 2.89 * 2$

$E =7.56 + 5.78$

$E =13.34$

7 0

3 years ago