Answer:
ΔP = 14.5 Ns
I = 14.5 Ns
ΔF = 5.8 x 10³ N = 5.8 KN
Explanation:
The mass of the ball is given as 0.145 kg in the complete question. So, the change in momentum will be:
ΔP = mv₂ - mv₁
ΔP = m(v₂ - v₁)
where,
ΔP = Change in Momentum = ?
m = mass of ball = 0.145 kg
v₂ = velocity of batted ball = 55.5 m/s
v₁ = velocity of pitched ball = - 44.5 m/s (due to opposite direction)
Therefore,
ΔP = (0.145 kg)(55.5 m/s + 44.5 m/s)
<u>ΔP = 14.5 Ns</u>
The impulse applied to a body is equal to the change in its momentum. Therefore,
Impulse = I = ΔP
<u>I = 14.5 Ns</u>
the average force can be found as:
I = ΔF*t
ΔF = I/t
where,
ΔF = Average Force = ?
t = time of contact = 2.5 ms = 2.5 x 10⁻³ s
Therefore,
ΔF = 14.5 N.s/(2.5 x 10⁻³ s)
<u>ΔF = 5.8 x 10³ N = 5.8 KN</u>
Answer: A material that does not easily allow a charge to pass through it is called an Plastic and rubber are good insulators. Many types of electric wire are covered with plastic, which insulates well. The plastic allows a charge to be conducted from one end of the wire to the other, but not through the sides of the wire.
Explanation:
Answer:
1
![t_a = 13.49 \ s](https://tex.z-dn.net/?f=%20t_a%20%20%3D%20%2013.49%20%5C%20%20s%20%20%20)
2
The distance is
Explanation:
From the question we are told that
The maximum speed of the cheetah is ![v = 103 \ km/h = 28.61 \ m/s](https://tex.z-dn.net/?f=v%20%3D%20%20103%20%5C%20%20km%2Fh%20%3D%20%2028.61%20%5C%20%20m%2Fs)
The maximum of gazelle is ![u = 76.5 \ km/h = 21.25 \ m/s](https://tex.z-dn.net/?f=u%20%3D%20%2076.5%20%5C%20%20km%2Fh%20%3D%20%2021.25%20%5C%20%20m%2Fs)
The distance ahead is ![d = 99.3 \ m](https://tex.z-dn.net/?f=d%20%3D%20%2099.3%20%5C%20%20m)
Let
denote the time which the cheetah catches the gazelle
Gnerally the equation representing the distance the cheetah needs to move in order to catch the gazelle is
![v* t_a = d + u* t_a](https://tex.z-dn.net/?f=%20v%2A%20t_a%20%3D%20d%20%2B%20%20u%2A%20t_a%20)
=> ![28.61 t_a = 99.3 + 21.25t_a](https://tex.z-dn.net/?f=%2028.61%20t_a%20%3D%2099.3%20%2B%20%2021.25t_a%20)
=> ![7.36 t_a = 99.3](https://tex.z-dn.net/?f=%207.36%20t_a%20%3D%2099.3%20%20)
=> ![t_a = 13.49 \ s](https://tex.z-dn.net/?f=%20t_a%20%20%3D%20%2013.49%20%5C%20%20s%20%20%20)
Now at t = 7.5 s
![7.5 v = D+ 7.5u](https://tex.z-dn.net/?f=7.5%20v%20%3D%20D%2B%20%207.5u%20)
=> ![28.61 * 7.5 = D + 21.25* 7.5](https://tex.z-dn.net/?f=%2028.61%20%2A%207.5%20%20%3D%20D%20%2B%20%2021.25%2A%207.5%20%20)
=> ![7.36 * 7.5 =D](https://tex.z-dn.net/?f=%207.36%20%2A%20%207.5%20%3DD%20%20)
=>
Hence the for the gazelle to escape the cheetah it must be 55.2 m
True, the definition of "centripetal force" is <span>a force that acts on a body moving in a circular path and is directed toward the center around which the body is moving.</span>
In order to answer this exercise you need to use the formulas
S = Vo*t + (1/2)*a*t^2
Vf = Vo + at
The data will be given as
Vf = final velocity = ?
Vo = initial velocity = 1.4 m/s
a = acceleration = 0.20 m/s^2
s = displacement = 100m
And now you do the following:
100 = 1.4t + (1/2)*0.2*t^2
t = 25.388s
and
Vf = 1.4 + 0.2(25.388)
Vf = 6.5 m/s
So the answer you are looking for is 6.5 m/s