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mezya [45]
3 years ago
11

A soccer player extends her lower leg in a kicking motion by exerting a force with the muscle above the knee in the front of her

leg. Suppose she produces an angular acceleration of 29.5 rad/s2 and her lower leg has a moment of inertia of 0.95 kg⋅m2 .
Physics
1 answer:
AlekseyPX3 years ago
7 0

Answer:

Answer:

28.025 Nm

Explanation:

Angular acceleration, α = 29.5 rad/s^2

oment of inertia, I = 0.95 kg m^2

The torque is defined as

τ = I x α

τ = 0.95 x 29.5

τ = 28.025 Nm

Thus, the torque is 28.025 Nm.

Explanation:

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Cart 1 has an initial velocity and hits cart 2 which is stationary. after a perfectly inelastic collision, the combined carts ar
Tomtit [17]

Option(a)  the mass of cart 2 is twice that of the mass of cart 1 is the right answer.

The mass of cart 2 is twice that of the mass of cart 1  is correct about the mass of cart 2.

Let's demonstrate the issue using variables:

Let,

m1=mass of cart 1

m2=mass of cart 2

v1 = velocity of cart 1 before collision

v2 = velocity of cart 2 before collision

v' = velocity of the carts after collision

Using the conservation of momentum for perfectly inelastic collisions:

m1v1 + m2v2 = (m1 + m2)v'

v2 = 0 because it is stationary

v' = 1/3*v1

m1v1 = (m1+m2)(1/3)(v1)

m1 = 1/3*m1 + 1/3*m2

1/3*m2 = m1 - 1/3*m1

1/3*m2 = 2/3*m1

m2 = 2m1

From this we can conclude that the mass of cart 2 is twice that of the mass of cart 1.

To learn more about inelastic collision visit:

brainly.com/question/14521843

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4 0
1 year ago
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Firdavs [7]

Answer:

the less shielding of electrons

6 0
3 years ago
Which statement is true about Gram negative organisms?
aliina [53]

Answer:

B, C and D are true.

<h3>Explanation:</h3>

A is false because they appear a pale reddish colour not purple.

3 0
3 years ago
HELPPP!!!!<br> if you double the force what is the change in acceleration
jenyasd209 [6]

As we know that acceleration is directly proportional to force, therefore as the force is doubled, acceleration gets doubled too.

8 0
3 years ago
A 350-kg roller coaster car starts from rest at point A and slides down a frictionless loop-the-loop (Pig. P7.41). (a) How fast
Leona [35]

Answer:

a)Velocity of car =v=16 m/s

b)Force against the track at point B=1.15*10^{4}N

Explanation:

Given mass of roller coaster=m=350 kg

Position of A=Ha=25 m

Position of B=Hb=12 m

Net potential energy=mg(ha-hb)

Net potential energy=(350)(9.80)(25-12)

Net potential energy=44590 J

Using energy conservation

net kinetic energy=net potential energy

(1/2)mv^2=mg(ha-hb)

m=350

velocity=v=16 m/s

b)There two force acting,centripetal force upward and gravity downward.

Thus net force acting will be

Net force=(mv^2/r)-mg

Net force=14933.33-3430

Net force=1.15*10^{4} N

3 0
3 years ago
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