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mezya [45]
3 years ago
11

A soccer player extends her lower leg in a kicking motion by exerting a force with the muscle above the knee in the front of her

leg. Suppose she produces an angular acceleration of 29.5 rad/s2 and her lower leg has a moment of inertia of 0.95 kg⋅m2 .
Physics
1 answer:
AlekseyPX3 years ago
7 0

Answer:

Answer:

28.025 Nm

Explanation:

Angular acceleration, α = 29.5 rad/s^2

oment of inertia, I = 0.95 kg m^2

The torque is defined as

τ = I x α

τ = 0.95 x 29.5

τ = 28.025 Nm

Thus, the torque is 28.025 Nm.

Explanation:

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The predicted location of Neptune was made possible because _____.
Neko [114]

Answer:

B. of a detailed study of uranus.

Explanation:

3 0
4 years ago
A car moves in a straight line at a speed of 68.5 km/h. How far (in km) will the car move in 5.45 minutes at this speed?
AlekseyPX
If you divide 68.5 km/h by 60 (the minutes in an hour) and then you get 1.141 then you multiply it by 5.45 and you get 6.222!


Your Answer is 6.222!!!!
5 0
3 years ago
Pls help fast !!!!!!!!!
Elodia [21]

Answer:

P and R me think

Explanation:

7 0
3 years ago
A disk between vertebrae in the spine is subjected to a shearing force of 600 N. Find its shear deformation, taking it to have t
Art [367]

Answer:

3.34×10^-6m

Explanation:

The shear modulus can also be regarded as the rigidity. It is the ratio of shear stress and shear strain

can be expressed as

shear stress/(shear strain)

= (F/A)/(Lo/ . Δx)

Stress=Force/Area

The sheear stress can be expressed below as

F Lo /(A *Δx)

Where A=area of the disk= πd^2/4

F=shearing force force= 600N

Δx= distance

S= shear modulus= 1 x 109 N/m2

Lo= Lenght of the cylinder= 0.700 cm=7×10^-2m

If we make Δx subject of the formula we have

Δx= FLo/(SA)

If we substitute the Area A we have

Δx= FLo/[S(πd^2/4]

Δx=4FLo/(πd^2 *S)

If we input the values we have

(4×600×0.7×10^-2)/10^9 × 3.14 ×(4×10^-2)^2

= 3.35×10^-6m

Therefore, its shear deformation is 3.35×10^-6m

A=area of the disk= πd^2/4

= [3.142×(4×10^-2)^2]/4

7 0
4 years ago
CuCl2
MArishka [77]

Answer:

<u>Copper ( II ) chloride </u>

Explanation:

<em>According to the nomenclature , </em>

  • <em>The metal ion name is followed by the non-metal ion</em>
  • <em>The oxidation state of the metal is to be mentioned in the brackets .</em>
  • <em>As CuCl_{2} has two Cl^- ions , and the net charge on the compound is zero , the charge on copper is :</em>

Cu^{x}+2Cl^-=0\\x-2=0\\x=2+

thus ,

⇒Cu^{2+}

∴ ,

The proper nomenclature is :

Copper ( II ) chloride

6 0
4 years ago
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