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kherson [118]
3 years ago
15

Fifteen joules of heat are added to a cylinder with a piston. The system uses 7 joules of energy to raise the piston upward. By

how much did the internal energy of the system increase? 2 joules 8 joules 15 joules 22 joules
Physics
2 answers:
nydimaria [60]3 years ago
6 0

Answer: 8j

Explanation:

Studentka2010 [4]3 years ago
4 0
The first law of thermodynamics states that:
\Delta U = Q-L
where 
\Delta U is the variation of internal energy of the system
Q is the heat absorbed by the system
L is the work done by the system on the surrounding.

In this problem, the system absorbs 15 J of heat, so Q=+15 J (with positive sign, since it is heat absorbed by the system) while the work done by the system is L=+7 J (with positive sign, since it is work done by the system), so the variation of internal energy is
\Delta U= Q-L=(15 J)-(7 J)=+8 J
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If a rocket-powered sled is accelerated to a speed of 440 m/s in 2.20 seconds, then what is the acceleration?
Margarita [4]

Answer:

 a = 200 m/s²

Explanation:

Given,

The initial speed of rocket-powered sled, u = 0

The final speed of rocket-powered sled, v = 440 m/s

Time taken to reach final speed, t = 2.20 s

The acceleration of the body is given by the change in velocity by time

                                       a = (v - u) / t

                                          = (440 - 0) / 2.20

                                          = 200 m/s²

Therefore, the acceleration of the rocket-powered sled, a = 200 m/s²

3 0
3 years ago
Two parallel plates 19 cm on a side are given equal and opposite charges of magnitude 2.0 ✕ 10^−9 C. The plates are 1.8 mm apart
Romashka [77]

Answer:

E   = 5291.00 N/C

Explanation:

Expression for capacitance is

C = \frac{\epsilon  A}{d}

where

A is area of square plate

D = DISTANCE BETWEEN THE PLATE

C = \frac{\epsilon\times(19\times 10^{-2})^2}{1.5\times 10^{-3}}

C = 24.06 \epsilon

C = 24.06\times 8.854\times 10^{-12} F

C =2.1\times 10^{-10} F

We know that capacitrnce and charge is related as

V = \frac{Q}{C}

 = \frac{2\tiimes 10^{-9}}{2.\times 10^{-10}}

v = 9.523 V

Electric field is given as

E = \frac{V}{d}

   = \frac{9.52}{1.8*10^{-3}}

E   = 5291.00 V/m

E   = 5291.00 N/C

5 0
2 years ago
two point charges of 3.4 μc and 6.6 μc are 0.20 m apart. what is the electrical potential energy of the system?
Daniel [21]

Explanation:

electrical potential = (6.6-3.4)/0.20

= 16 uc/m

8 0
2 years ago
An atom of uranium 238 emits an alpha particle (an atom of He) and recoils with a velocity of 1.895 * 10^ 5 m/sec . With velocit
lora16 [44]

<u>Answer:</u> The velocity of released alpha particle is 1.127\times 10^7m/s

<u>Explanation:</u>

According to law of conservation of momentum, momentum can neither be created nor be destroyed until and unless, an external force is applied.

For a system:

m_1v_1=m_2v_2

where,

m_1\text{ and }v_1 = Initial mass and velocity

m_2\text{ and }v_2 = Final mass and velocity

We are given:

m_1=238u\\v_1=1.895\times 10^{5}m/s\\m_2=4u\text{ (Mass of }\alpha \text{ -particle)}\\v_2=?m/s

Putting values in above equation, we get:

238\times 1.895\times 10^5=4\times v_2\\\\v_2=\frac{238\times 1.895\times 10^5}{4}=1.127\times 10^7m/s

Hence, the velocity of released alpha particle is 1.127\times 10^7m/s

4 0
3 years ago
Give 2 reasons for fitting heavy commercial vehicles with many tyres​
forsale [732]
Better weight distribution and more stability
4 0
2 years ago
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