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liraira [26]
3 years ago
14

what happens to the molecules in a can of soda that is at 20c when it is placed in a chest of ice water that is at -2c

Physics
1 answer:
Alla [95]3 years ago
6 0

Explanation:

The molecule in the can of soda will begin to lose their kinetic energy and become more order. In short, the entropy of the molecules in the can will begin to reduce drastically.

  • Since the soda in the can is at a higher temperature, there would be transfer of heat until thermal equilibrium is attained.
  • In due process, the fast paced soda particles will begin to lose some of its energy to the water in the ice chest.
  • This will stop until thermal equilibrium is attained.

Therefore, the molecules in the can will have a lower average kinetic energy.

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Five groups of four vectors are shown below. All magnitudes of individual vectors are equal. Please rank the groups based on the
valkas [14]

With the addition of vectors we can find that the correct answer is:

   C)   Q> P > R =  S > T

The addition of vectors must be done taking into account that they have modulus and direction. The analytical method is one of the easiest methods, the method to do it is:

  • Set a Cartesian coordinate system
  • Decompose vectors into their components in a Cartesian system
  • Perform the algebraic sums on each axis
  • Find the resultant vector using the Pythagoras' Theorem to find the modulus and trigonometry to find the direction.

In this exercise indicate that the modulus of all vectors is the same, suppose that the value of the modulus is A.

We fix a Cartesian coordinate system with the horizontal x axis and the vertical y axis, we can see that we do not need to perform any decomposition, so we perform the algebraic sums

Diagram P

x-axis

         x = 2A

y-axis  

         y = 2A

The modulus of the resulting vector can be found with the Pythagorean Theorem

          P = \sqrt{x^2+y^2}

          P = \sqrt{4A^2 +4A^2 }= \sqrt{8}  \  A

          P = 2 √2  A

         

Diagram Q

x-axis

        x = 3A

y-axis  

        y = A

Resulting

       Q = \sqrt{x^2+y^2}

       Q =\sqrt{9A^2 + A^2 }  

       Q = \sqrt{10} \ A

       

Diagram R

x- axis

       x = 0

y-axis

        y = 2 A

Resulting

       R =\sqrt{4A^2 + 0}  

       R = \sqrt{4} \ A

Diagram S

x-axis

       x = 2 A

y-axis

        y = 0

 

Resulting

       S = 2A

Diagram T

x- axis

      x = 0

y-axis  

      y = 0

Resultant T = 0

We order the diagram from highest to lowest

    Q> P> R = S> T

When reviewing the different answers, the correct one is:

   C.  Q> P> R = S> T

Learn more about adding vectors here:

brainly.com/question/14748235

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