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e-lub [12.9K]
3 years ago
15

I have 3 equations 9x+6, 2(5x-3) and 5y+14 how do i solve for x?

Mathematics
1 answer:
snow_tiger [21]3 years ago
8 0
Set the equation equal to zero.

9x+6=0
Subtract 6 from both sides
9x = -6
Divide both sides by 9
x=-6/9
or -2/3

2(5x-3)=0
Distribute
10x-6=0
add 6 to both sides
10x=6
Divide by 10 on both sides
x=6/10 or 4/5

5y+14=0
-14 from both sides
5y=-14
divide both sides by 5
y=-14/5
or -2 and 4/5
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The integrating factor if e^{^{ \int \dfrac{9}{250}\ dt}} = e^{^{ \dfrac{9t}{250} }}

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e^{^{ \dfrac{9t }{250}}} \ \ x(t) = \int 21 e^{\dfrac{9t}{250}} \ dt + C

e^{^{ \dfrac{9t }{250}}} \ \ x(t) =  21 \times \dfrac{250}{9}e^{\dfrac{9t}{250}} + C

x(t) = \dfrac{1750}{3}+Ce^{^{\dfrac{-9t}{250}}}     at  t = (0) and x(0) = 100 lb

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C = - \dfrac{1450}{3}

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after time t = 1 minute i.e 60 s

x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-9 \times 60}{250}}}

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