The conclusion is that since the value of 0.028 is less than 0.05 so we reject the null hypothesis at 5% level of significance and conclude that the mean of the difference in SAT writing scores for all students who take SAT prep class is equal to 0.
<h3>What is a null hypothesis?</h3>
A null hypothesis is a hypothesis that there is no significant difference between specified populations, any observed difference being due to sampling error.
Here, the effect of a one-day SAT prep class at a 5% level of significance was assessed. Since the value of 0.028 is less than 0.05 so we reject the null hypothesis at 5% level of significance and conclude that the mean of the difference in SAT writing scores for all students who take SAT prep class is equal to 0.
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Answer:
135.48
Step-by-step explanation:
g00gl3
Best answer is A, 778,000.
Answer:
2 candies to each friend
Step-by-step explanation:
This is a division problem. You would do:
10/5 as there are 10 candies to share and 5 friends to give them to. This would yield a result of 2 candies per friend.
Answer:
The parameters of this exponential distribution is 
= 
.
Step-by-step explanation:
We are given that the random variable X is known to be exponentially distributed and let X be the time it takes for a person to choose a birthday gift, where X has an average value of 27 minutes.
<u><em>So, X = time it takes for a person to choose a birthday gift</em></u>
The probability distribution function of exponential distribution is given by;
where, = parameter of distribution.
Now, the mean of exponential distribution is = 
which is given to us as average value of 27 minutes that means 
.
So, X ~ Exp( ) .
Therefore, the parameter of this exponential distribution is .
