Reflect vertices D(-2,14),O(-3,7),G(4,-3) across y-axis. What are the coordinates of D’ O’ G’
1 answer:
You might be interested in
Answer:
The correct option is;
Yes, the line should be perpendicular to one of the rectangular faces
Step-by-step explanation:
The given information are;
A triangular prism lying on a rectangular base and a line drawn along the slant height
A perpendicular bisector should therefore be perpendicular with reference to the base of the triangular prism such that the cross section will be congruent to the triangular faces
Therefore Marco is correct and the correct option is yes, the line should be perpendicular to one of the rectangular faces (the face the prism is lying on).
Answer:
a) p(x) = 300 - 3
b) P(x) = -3 x² + 285 x
c) Price of per room per day = $ 157.5
when Number of rooms occupied , x = 47.5
Step-by-step explanation:
Given - A motel owner observes that when a room is priced at $60 per day, all 80 rooms of the motel are occupied. For every $3 rise in the charge per room per day, one more room is vacant. Each occupied room costs an additional $15 per day to maintain.
To find - a) Find the demand function, expressing p, the price charged for each room per day, as a function of x, the number of rooms occupied.
b) Find the profit function P(x).
c) Find the price of per room per day the motel should charge in order to maximize its profit.
Proof -
a)
Let
(x, y) be the point
where x represents number of rooms occupied
and y represents price of room per day.
Now,
Given that,
a room is priced at $60 per day, all 80 rooms of the motel are occupied.
So, point becomes (80, 60)
And given that For every $3 rise in the charge per room per day, one more room is vacant.
So, point becomes (79, 63)
Now, we have two points (80, 60), (79, 63)
Let us assume that,
p(x) be the price charged for each room per day
Now,
By using point - slope formula , we get
p -60 =
⇒p -60 = (-3)(x-80)
⇒p-60 = 240 -3 x
⇒p(x) = 240 + 60 -3 x
⇒p(x) = 300 - 3 x
b)
Given that,
Each occupied room costs an additional $15 per day to maintain.
Let C(x) be the cost function,
Then C(x) =15 x
now,
Revenue function,
R(x) =x*p
= x*(300 -3 x )
= 300 x - 3 x²
⇒R(x) = 300 x - 3 x²
Now,
We know
Profit function = Revenue function - Cost function
⇒P(x) = R(x)-C(x)
⇒P(x) = (300 x -3 x²) -15 x
⇒P(x) = -3 x² + 285 x
c)
P'(x) = -6 x +285
For Maximize profit , Put P'(x) = 0
⇒-6 x+ 285 =0
⇒6 x= 285
⇒x =
⇒x= 47.5
∴ we get
Maximize profit is when price, p = 300 - 3x
= 300 -3(47.5)
= $157.5
⇒Price of per room per day = $ 157.5
when Number of rooms occupied , x = 47.5