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xz_007 [3.2K]
3 years ago
6

-7(-5v-3u 4) use the distributive property to remove the parentheses

Mathematics
1 answer:
Marrrta [24]3 years ago
3 0
Distributeiv poepty
a(b+c)=ab+ac

remember that (-) times (-)=(+)
and (+) TIMES (-)=(-)

SO
<span>-7(-5v-3u+4)=(-7)(-5v)+(-7)(-3u)+(-7)(4)=35v+21u-28</span>
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CAN ANYONE HELP ME PLEASE!!!!!!
HACTEHA [7]
Not sure if this helps

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Name the property the equation illustrates.
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I think it is the associative property of Addition
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A = {1, 3, 5, 7, 9}
kondor19780726 [428]
The \cap symbol means intersection, so everything that is in both sets, and the \cup symbol means union, so the two sets combined.

B \cup C = \{1, 2, 4, 5, 6, 7, 8, 9, 10\} = S
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Which expressions are equivalent to 2(b+3c)?
Rina8888 [55]

Answer:

B. (b+3c)+(b+3c)

C. 2(b)+2(3c)

Step-by-step explanation:

we have

2(b+3c)

Distribute the number 2

2(b+3c)=2b+2(3c)=2b+6c

Verify each case

case A) 3(b+2c)

distribute the number 3

3(b+2c)=3b+3(2c)=3b+6c

3b+6c \neq 2b+6c

therefore

Choice A is not equivalent to the given expression

case B) (b+3c)+(b+3c)

Combine like terms

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therefore

Choice B is equivalent to the given expression

case C) 2(b)+2(3c)

Multiply both terns by 2

2(b)+2(3c)=2b+6c

2b+6c= 2b+6c

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Choice C is equivalent to the given expression

6 0
3 years ago
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omeli [17]

Answer:

1) A. H0: p = 0.30

HA: p not equal to 0.30

2) A. The Independence Assumption is met.

C. The Randomization Condition is met.

D. The Success/Failure Condition is met.

3) Test statistic z = 2.089

P-value = 0.0367

4) C. Reject H0. There is sufficient evidence to suggest that the percentage of bills paid by medical insurance has changed.

Step-by-step explanation:

1) This is a hypothesis test for a proportion.

The claim is that there is a significant change in the percent of bills being paid by medical​ insurance.

As we are looking for evidence of a difference, no matter if it is higher or lower than the null hypothesis proportion, the alternative hypothesis is defined by a unequal sign.

Then, the null and alternative hypothesis are:

H_0: \pi=0.3\\\\H_a:\pi\neq 0.3

2) Cheking the conditions:

The independence assumption and the randomization condition are met as the bills were selected randomly from the population.

The 10% condition can not be checked, as we do not know the size of the population.

The success/failure condition is met as the products np and n(1-p) are bigger than 10 (the number of successes and failures are both bigger than 10).

3) The significance level is assumed to be 0.05.

The sample has a size n=9260.

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\text{P-value}=2\cdot P(z>2.089)=0.0367

As the P-value (0.0184) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that there is a significant change in the percent of bills being paid by medical​ insurance.

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3 years ago
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