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3 years ago

A pair of linear equations is shown below:

Mathematics

2 answers:

iren [92.7K]3 years ago

5 0

Answer:

<em>A. the first line has y-intercept = 5 and slope = -3, </em>

<em>and the second line has y-intercept = 2 and slope = 1.</em>

Explanation:

The given pair of lines are as follows,

$y=-3x+5$

$y=x+2$

The general slope-intercept form of straight line is,

$y=mx+c$

where,

m = slope of the line

c = y-intercept

Comparing this with the line equations,

slope of 1st line = -3, y-intercept of 1st line = 5

slope of 2nd line = 1, y-intercept of 2nd line = 2

*The point of intersection is attached below.

Arlecino [84]3 years ago

3 0

Simple, it's A.

y=-3x+5
and
y=x+2

The slope for the first line is m=-3 and y-intercept y=5

The slope for the second line is m=1 and y-intercept y=2

The only logical answer is A. Thus, your answer.

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3 years ago

Select the correct answer.

aleksklad [387]

Answer:

R(2, 4)

Step-by-step explanation:

The general equation for a circle centered at (h,k) with radius, R, is

(x-h)^2 + (y-k)^2 = R^2

Putting the values in formula,

(x-6)^2 + (y-1)^2 = 5^2

Putting the coordinates (2, 4) of the answer B(2-6)^2 + (4-1)^2 = 25

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R.H.S = L.H.S

So according to the above solution,

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2 years ago

Equalenlent expression to 24y+16 with distributive propertie

Inessa [10]

8(3 y+2)

Step-by-step explanation:

To apply the distributive property you need to use parentheses and multiply outside numbers with inside numbers or terms

24 y+16

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3 years ago

Find the 11th term of this sequence. -10,20,-40,80...

Morgarella [4.7K]

The difference is not constant therefore there cannot be an 11th term that is correct.

6 0

3 years ago

Read 2 more answers

The function f(x) = { x + 1 is used to complete this Which statements are true of the given function? Check all that apply. tabl

Dmitry [639]

Answer:

Options (1) and (5)

Step-by-step explanation:

Expression that defines the function is,

$f(x)=\frac{1}{2}x+\frac{3}{2}$

Option 1

$f(-\frac{1}{2})=\frac{1}{2}(-\frac{1}{2})+\frac{3}{2}$

$=-\frac{1}{4}+\frac{3}{2}$

$=-\frac{1}{4}+1+\frac{1}{2}$

$=1+\frac{1}{4}$

$=1\frac{1}{4}$

So, $f(-\frac{1}{2} )=-2$ is false.

Option 2

f(0) = $\frac{1}{2}(0)+\frac{3}{2}$

= $\frac{3}{2}$

True.

Option 3

f(1) = $\frac{1}{2}(1)+\frac{3}{2}$

= $\frac{3+1}{2}$

= 2

Therefore, f(1) = -1 is false.

Option 4

$f(2)=\frac{1}{2}(2)+\frac{3}{2}$

$=1+1+\frac{1}{2}$

$=2\frac{1}{2}$

Therefore, f(2) = 1 is false.

Option 5

f(4) $=\frac{1}{2}(4)+\frac{3}{2}$

$=2+\frac{3}{2}$

$=\frac{4+3}{2}$

$=\frac{7}{2}$

True.

Options (1) and (5) are the correct options.

5 0

3 years ago