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pav-90 [236]
3 years ago
5

Convert log7(7^x) = y to exponential form.

Mathematics
1 answer:
posledela3 years ago
4 0
log _{7} (7^x) = y -> 7^y = 7^x

Rule x=logb(y) -> y = b^x
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\sf{3. \ \ Given : \dfrac{2}{3} - \dfrac{5}{4} + \dfrac{7}{2}}

Let us solve the first two fractions : The LCM of 3 and 4 is 12

\sf{\implies \dfrac{4(2) - 5(3)}{12} + \dfrac{7}{2}}

\sf{\implies \dfrac{8 - 15}{12} + \dfrac{7}{2}}

\sf{\implies \dfrac{-7}{12} + \dfrac{7}{2}}

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\sf{\implies \dfrac{-7 + 7(6) }{12}}

\sf{\implies \dfrac{-7 + 42}{12}}

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\sf{\implies 2 \dfrac{11}{12}}

---------------------------------------------------------------------------------------

\sf{4. \ \ Given : \dfrac{(2 - 7)^2 + 5}{3}}

\sf{\implies \dfrac{(-5)^2 + 5}{3}}

\sf{\implies \dfrac{25 + 5}{3}}

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