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AlladinOne [14]
2 years ago
5

Help? which one should I choose

Mathematics
1 answer:
Paladinen [302]2 years ago
8 0

Answer:

the second

Step-by-step explanation:

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34,000 people attended a ballgame at a stadium that offers two kind of seats: general admission and reserved. The day's receipts
hoa [83]

Answer:

The number of people who paid $ 12 for reserved seat is 5,000

The number of people who paid $ 4 for general seat is 29,000  

Step-by-step explanation:

Given as :

The total number of people attending a ballgame = 34,000

The total receipt of the ticket's seat = $ 176,000

The amount pad for reserved seat = $ 12

The amount paid for general admission = $ 4

Let The number of people for reserved seat = r

And The number of people for general admission = g

Now, According to question

The total number of people attending a ballgame =  The number of people for reserved seat + The number of people for general admission

or, r + g = 34,000           ...........1

The total receipt of the ticket's seat = The amount pad for reserved seat × The number of people for reserved seat + The amount paid for general admission × The number of people for general admission

Or, $ 12 × r + $  ×4 g = $ 176,000           .........2

or, $ 12 × ( r + g ) = $ 12 × 34000

Or, $ 12 r + $ 12 g = $ 408,000

Solving equation

( $ 12 r + $ 12 g ) - ($ 12 r + $ 4 g ) = $ 408,000 - $ 176,000

Or, ( $ 12 r - $ 12 r ) + ( $ 12 g - $ 4 g ) = $ 232,000

Or 0 + 8 g = 232,000

∴  g = \frac{232000}{8}

I.e g = 29,000

So , The number of people for general admission = g = 29,000

Put the value of g in Eq 1

I.e  r + g = 34,000  

or , r = 34,000 - g

∴  r = 34000 - 29000

I.e r = 5,000

So, The number of people for reserved seat = r = 5,000

Hence The number of people who paid $ 12 for reserved seat is 5,000

And The number of people who paid $ 4 for general seat is 29,000  Answer

6 0
3 years ago
What is the volume of the shape?
rodikova [14]

Answer:

volume: 1/3 a²h

= 1/3 ×2²x6

= 8 feet³

6 0
3 years ago
Increase £25 by 25% . .
Stells [14]
£31.25 homie yuh yuh
8 0
3 years ago
A 500500-gallon tank initially contains 200200 gallons of brine containing 100100 pounds of dissolved salt. brine containing 11
mixer [17]
Let A(t) denote the amount of salt in the tank at time t. We're given that the tank initially holds A(0)=100 lbs of salt.

The rate at which salt flows in and out of the tank is given by the relation

\dfrac{\mathrm dA}{\mathrm dt}=\underbrace{\dfrac{11\text{ lb}}{1\text{ gal}}\times\dfrac{44\text{ gal}}{1\text{ min}}}_{\text{rate in}}-\underbrace{\dfrac{A(t)}{200+(44-11)t}\times\dfrac{11\text{ gal}}{1\text{ min}}}_{\text{rate out}}
\implies A'(t)+\dfrac{11}{200+33t}A(t)=484

Find the integrating factor:

\mu(t)=\exp\left(\displaystyle\int\frac{11}{200+33t}\,\mathrm dt\right)=(200+33t)^{1/3}

Distribute \mu(t) along both sides of the ODE:

(200+33t)^{1/3}A'(t)+11(200+33t)^{-2/3}A(t)=484(200+33t)^{-1/3}
\bigg((200+33t)^{1/3}A(t)\bigg)'=484(200+33t)^{-1/3}
A(t)=484\displaystyle\int(200+33t)^{-1/3}\,\mathrm dt
A(t)=22(200+33t)^{2/3}+C

Since A(0)=100, we get

100=22(200)^{2/3}+C\implies C\approx-652.39

so that the particular solution for A(t) is

A(t)=22(200+33t)^{2/3}-652.39

The tank becomes full when the volume of solution in the tank at time t is the same as the total volume of the tank:

200+(44-11)t=500\implies 33t=300\implies t\approx9.09

at which point the amount of salt in the solution would be

A(9.09)\approx733.47\text{ lb}
4 0
3 years ago
How many solutions does the equation 4x + 8 = − 2 − 2 + 5x have?
ikadub [295]

Answer:

12 =x

There is one solution

Step-by-step explanation:

4x + 8 = − 2 − 2 + 5x

Combine like terms

4x+8 = -4+5x

Subtract 4x from each side

4x-4x+8 = -4+5x-4x

8 = -4+x

Add 4 to each side

8+4 = -4+4+x

12 =x

6 0
3 years ago
Read 2 more answers
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