2x+3y=60 solve for x...
x=(60-3y)/2
p=xy^3, using x from above:
p=y^3(60-3y)/2
p=(60y^3-3y^4)/2
dp/dy=(180y^2-12y^3)/2
dp/dy=90y^2-6y^2
dp/dy=0 when:
90y^2-6y^3=0
6y^2(15-y)=0, we know y>0 so
y=15, since x=(60-3y)/2
x=7.5
(We solved it this way because otherwise you get quartic equations and cubic derivatives, yuck :P)
(1,7), since that's the point where both lines intersect.
Use set builder notation to give a description of each of these sets. a) {0,3,6,9,12} b) {−3,−2,−1,0,1,2,3} c) {m,n,o,p}
attashe74 [19]
Answer:

Step-by-step explanation:
The set is a well-defined collection of objects.
Set builder form describes the set by stating the property of each of its elements.
a)

W is a set of whole numbers.
b)

c)

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