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Alexus [3.1K]
3 years ago
7

Another question... this was all the information I was given and I'm a tad confused as to how to go about solving it... help ple

ase??? Thank you so much!!!
Julia needs to cut a 15m rope into 20 equal pieces. Calculate the length of each piece in cm
Mathematics
2 answers:
Sholpan [36]3 years ago
4 0
Argh! My answer was erased!

We need to cut a 15m rope into 20 equal pieces. Written mathematically, it is as follows:
15/20 = length of rope segment in meters (a)
15/20 = a

Simplify
3/4 = a

In meters, each rope segment is 3/4m long.  But, we don't want meters.  We want centimeters.

100 cm = 1 m

3/4(100) = length of rope segment in centimeters (x)
3/4(100) = x

300/4 = x
75 = x

Each segment of rope is 75 cm long.
Lana71 [14]3 years ago
3 0
The rope needs to be cut into 20 pieces, so 15/20, this will give you 3/4 of a meter per piece. Multiply 100 (100 cm in a meter), .75*100= 75 centimeters in a piece...
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If x and y are two nonnegative numbers and the sum of twice the first ( x ) and three times the second ( y ) is 60, find x so th
stepan [7]
2x+3y=60 solve for x...

x=(60-3y)/2

p=xy^3, using x from above:

p=y^3(60-3y)/2

p=(60y^3-3y^4)/2

dp/dy=(180y^2-12y^3)/2

dp/dy=90y^2-6y^2

dp/dy=0 when:

90y^2-6y^3=0

6y^2(15-y)=0, we know y>0 so

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3 years ago
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zloy xaker [14]
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Use set builder notation to give a description of each of these sets. a) {0,3,6,9,12} b) {−3,−2,−1,0,1,2,3} c) {m,n,o,p}
attashe74 [19]

Answer:

\left \{ 0,3,6,9,12 \right \}=\left \{ x;x=3n\,,\,n\,\varepsilon \,W ;\,\,n\leq 4\right \}\\\left \{ -3,-2,-1,0,1,2,3 \right \}=\left \{ x;x=\pm n;\,\,n=0,1,2,3 \right \}\\\left \{ m,n,o,p \right \}=\left \{ x;x \,\,is\,\,an\,\,alphabet\,\,after\,\,l\,\,and\,\,before\,\,q \right \}

Step-by-step explanation:

The set is a well-defined collection of objects.

Set builder form describes the set by stating the property of each of its elements.

a)

\left \{ 0,3,6,9,12 \right \}=\left \{ x;x=3n\,,\,n\,\varepsilon \,W ;\,\,n\leq 4\right \}

W is a set of whole numbers.

b)

\left \{ -3,-2,-1,0,1,2,3 \right \}=\left \{ x;x=\pm n;\,\,n=0,1,2,3 \right \}

c)

\left \{ m,n,o,p \right \}=\left \{ x;x \,\,is\,\,an\,\,alphabet\,\,after\,\,l\,\,and\,\,before\,\,q \right \}

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Answer:

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Step-by-step explanation:

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