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lesantik [10]
3 years ago
14

PLEASE HELP IM SO CONFUSED Which expression gives the volume of a sphere with radius 8?

Mathematics
1 answer:
kumpel [21]3 years ago
3 0
The answer is B :))
im sure
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(2/5) + ( -1/4). Show your work by using the “butterfly” method.
pashok25 [27]

Answer:

0.15

Step-by-step explanation:

Step 1: Make sure the bottom numbers (the denominators) are the same

Step 2: Add the top numbers (the numerators), put that answer over the denominator

Step 3: Simplify the fraction (if needed)

3 0
3 years ago
On a number line, what is the distance between -8 and -2?<br> A-10<br> B-6<br> C6<br> D10
snow_tiger [21]

Answer:

the answer is c) or 6. I hope it helps

7 0
3 years ago
Read 2 more answers
Solve the literal equation ab+c=d in terms of a
s2008m [1.1K]
ab+c=d 

ab=d-c  |Subtract \ c \ from \ both \ sides| 

<span>a= \dfrac{d-c}{b}  Divide \ both \ sides \ by \ b</span>
5 0
3 years ago
A store is having a sale where movies are 15% off their original price. A movie originally cost $25. how much money will be save
Aleksandr-060686 [28]
Since you are asked how much mopney sill be saved, you just need to find out the amount of the discount.

15% of $25 =

= 15% * $25

= 0.15 * $25

= $3.75

The amount saved is $3.75.
8 0
4 years ago
Sea un cuadrado de 2 pulgadas de lado uniendo los puntos medios se obtiene otro cuadrado inscrito en el anterior si repetimos es
Ne4ueva [31]

Answer:

1) La serie geométrica formada es

4, 2, 1,..., ∞

2) La suma al infinito de las áreas de los cuadrados es 8 in.²

Step-by-step explanation:

1) El área del primer cuadrado, a₁ = 2² = 4 pulgadas²

El área del siguiente cuadrado, a₂ = (√ (1² + 1²)) ² = (√2) ² = 2 pulg²

El área del siguiente cuadrado, a₃ = ((√ (2) / 2) ² + (√ (2) / 2) ²) = 1 pulg²

Por lo tanto, la razón común, r = a₂ / a₁ = 2/4 = a₃ / a₂ = 1/2

Las áreas de los cuadrados progresivos forman una progresión geométrica como sigue;

4, 4×(1/2), 4 ×(1/2)²,...,4×(1/2)^{\infty}

De donde obtenemos la serie geométrica formada de la siguiente manera;

4, 2, 1,..., ∞

2) La suma de 'n' términos de una progresión geométrica hasta el infinito para -1 <r <1 se da como sigue;

S_{\infty} = \dfrac{a}{1 - r}

Por lo tanto, la suma de las áreas de los cuadrados hasta el infinito se obtiene sustituyendo los valores de 'a' y 'r' en la ecuación anterior de la siguiente manera;

La \ suma \ al \ infinito \ del \ cuadrado \ S_{\infty}  = \dfrac{4 \ in.^2}{1 - \dfrac{1}{2} } = \dfrac{4 \ in.^2}{\left(\dfrac{1}{2} \right)} = 2 \times 4 \ in.^2= 8 \ in.^2

La suma al infinito de las áreas de los cuadrados, S_{\infty} = 8 in.²

7 0
3 years ago
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