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Alla [95]
3 years ago
14

sam has five favorite football teams, and every week, he puts their flags on his flagpole in random order a. in a given week, ho

w many different ways can he arrange the flags? b. if he only has room for three of the flags on his flagpole, how many different ways can they be arranged?
Mathematics
1 answer:
pav-90 [236]3 years ago
3 0
A. This is an example of a situation making use of the concept of Fundamental Principles of Counting. On the first spot, Sam may choose from the five available flags. On the next spot, he can only choose from four flags. This goes on until no more flag is left. For short, there are 5! ways. This is equal to 120.

b. Since only 3 out of the five flags can be used and the arrangement is important, make use of Permutation. The answer is 5P3 = 60. There are 60 ways. 
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Answer:

you can make 14 muffins

Step-by-step explanation:

To get this answer you first need to know that 1 cup makes 8 muffins. Next know that there's 1 3/4 cups of flour. Because you know that 1 cup makes 8 muffins you need to figure out how many muffins 3/4 a cup of flour can make. To do this you divide 8 by 4. Hence 8 divided by 4 is 2. So know you know that for every 1/4 cup you can make 2 muffins. Now since there's 3/4 cup of flour you then multiply 2 by 3 which is 6. Now you have to add 1 cup ( 8 muffins) to 3/4 cup ( 6 muffins ) of flour which then equals 14. You then get the answer , 1 3/4 cups of flour can make 14 muffins. Hope this helped ;)

6 0
3 years ago
Simplify the complex fraction.<br> Simplify.<br> 5<br> 9<br> 4<br> 15
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im confused?

Step-by-step explanation:

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5 0
2 years ago
If x = 2 and y = 1, then 3(y – 1) + 2x2 =
abruzzese [7]
3(1-1) +2x2

3-1+4

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6 0
3 years ago
Read 2 more answers
PLEASE HELP MY FUTURE DEPENDS ON THIS QUESTION 6
oksano4ka [1.4K]

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Step-by-step explanation:

7 0
2 years ago
HELP PLEASEEE!!
Luden [163]

\left[\begin{array}{ccc}2&6&3\\-5&1&4\end{array}\right]

R1 ÷ 2  = \left[\begin{array}{ccc}1&3&1.5\\-5&1&4\end{array}\right]

R2 ÷ -5 = \left[\begin{array}{ccc}1&3&1.5\\1&-0.2&-0.8\end{array}\right]

R2: R1 - R2  = \left[\begin{array}{ccc}1&3&1.5\\0&3.2&2.3\end{array}\right]

R2 ÷ 3.2 =  \left[\begin{array}{ccc}1&3&1.5\\0&1&0.71875\end{array}\right]

R1: R1 - 3R2 = \left[\begin{array}{ccc}1&0&0.65625\\0&1&0.71875\end{array}\right]

Answer: x = 0.65625, y = 0.71875

8 0
3 years ago
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