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nika2105 [10]
3 years ago
10

How many atom will be present in2.7 g of aluminumal=22 na=6.02×^23​

Chemistry
1 answer:
Elden [556K]3 years ago
5 0

Answer:

just add ⅜⁸ and ⅖⁵

Explanation:

because I was told it awnsers almost all questions

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