Answer:
A,D,E,F
Explanation:
A.Ketones generally have lower boiling points in relation to alcohols because of the intermolecular hydrogen bonds.
D.Aldehyde group is known for this C=O group in which Carbon has a double bond with Oxygen.
E. Aldehydes and Ketones can’t hydrogen bond with each other but they can hydrogen bond with water
F. Formaldehyde used in the laboratory for preservation is a liquid at room temperature while propanol which has more carbon is gaseous
B is wrong because as the Carbon increases the solubility in water decreases
C is wrong because 2-butanol has a bp of 100 degree celsius while butanal has a bp of around 74.
Let <span>A= ebc </span>
<span> 0.765 = 86,300*1.3*c </span>
<span>
Solve for c = approximately 7E-6 Molar
= mols/L soln. </span>
<span>g = 7E-6*893.49
= about 0.006 g chlorophyll/L soln. </span>
<span>
1000 x 0.785 = 785 g ethanol. </span>
<span>Conc. = about 0.006g chlorophyll/785 g soln. </span>
<span>
Change that to ppm. by using formula:
(0.006/785)*1E6</span>
There are two atoms of hydrogen molecules.
The answer is <span>increasing the surface area of Fe(s) and increasing the concentration of HCl(aq).
the rate of reaction can be increased if the interaction between the reactants in better. by increasing the surface area of a solid, such as Fe, you make more possible each molecule of Fe to interact with HCl. Also, by increasing the concentration of HCl, it mean there is more molecule of HCl to interact with Fe.</span>
