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liq [111]
3 years ago
12

How much energy is required to heat 14 grams of water from 18 degrees Celsius to 47 degrees Celsius

Chemistry
1 answer:
Alborosie3 years ago
5 0

Answer:

Q=1,698.7J

Explanation:

Hello!

In this case, since the calculation of the required energy is performed via the following equation:

Q=mC(T_f-T_i)

Thus, since the mass is 14 g, specific heat is 4.184 J(g*°C) and the temperatures are 47 °C and 18 °C respectively, the resulting energy is:

Q=14g*4.184\frac{J}{g\°C}(47°C-18°C)\\\\Q=1,698.7J

Best regards!

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